Given,
The sum of three integers is 92
So,
Let,
The first integer be "x"
The second integer be "y"
The third integer be "z"
Now,
According to the question,
y = 3x ..............equation (1)
z = 2x - 10 .............. equation (2)
x + y + z = 92 ..............equation (3)
Now,
Substituting the value of "y" and "z" from equation (1) and (2), we get,
x + (3x) + (2x - 10) = 92
x + 3x + 2x - 10 = 92
6x - 10 = 92
6x = 92 + 10
x = 102 / 6
x = 17
Now,
substituting the value of "x" in equation (1)
y = 3 (17)
y = 51
Now,
Substituting the value of "x" in equation (2),
z = 2 (17 ) - 10
z = 34 - 10
z = 24
So, the numbers are 17, 51 and 24
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Answer:
i have made it in above picture hope it helps
According to Vieta's Formulas, if
are solutions of a given quadratic equation:
Then:
is the completely factored form of
.
If choose
, then:
So, according to Vieta's formula, we can get:
But
:
![d^4-8d^2+16=(d^2-4)^2=[(d+2)(d-2)]^2=(d+2)^2(d-2)^2](https://tex.z-dn.net/?f=d%5E4-8d%5E2%2B16%3D%28d%5E2-4%29%5E2%3D%5B%28d%2B2%29%28d-2%29%5D%5E2%3D%28d%2B2%29%5E2%28d-2%29%5E2)
The Correct option is -4
because every other terms result in value = 4, where's -4 is the only different one hence doesn't belongs yo other three
