Let
x = loaves of bread
y = batches of muffins
You must make a system of two equations with two unknowns that describe the problem
3.5x + 2.5y = 17 --- (1)
0.75x + 0.75y = 4.5 --- (2)
Resolving we have
x = 6-y (from (2))
replacing in (1)
3.5 (6-y) + 2.5y = 17
21 - 3.5y + 2.5y = 17
y = 21-17 = 4
Then substituting in (2)
x = 6-y = 6-4 = 2
Answer
Helena could bake:
2 loaves of bread
4 batches of muffins
Answer:
A rectangular prism has eight vertices and a rectangular pyramid has five.Step-by-step explanation:
Answer:
1912
Step-by-step explanation:
Answer:
<u><em>37 decreased by 20% is </em></u><u><em>29.6.</em></u>
Step-by-step explanation:
<u><em>To do this, what we do is simply </em></u><u><em>take 20% of 37 and subtract it from 37.</em></u>
<u><em>20% of 37.</em></u><u><em> A trick to easily figure this out is </em></u><u><em>multipling 37 by 20 and dividing by 100.</em></u>
<u><em>37*20 = 740</em></u>
<u><em>740 / 100 = 7.40</em></u>
<u><em>37 - 7.40 = 29.6</em></u>
<u><em>37 decreased by 20% is </em></u><u><em>29.6.</em></u>
You can get the tens digit of any number <em>n</em> by computing the quotient
(<em>n</em> (mod 100)) / 10
and ignoring the remainder.
Taking the given sum (mod 100) gives
7! + 8! + … + 2006! ≡ 7! + 8! + 9! (mod 100)
since the last 1997 terms (i.e. 10! up to 2006!) in the sum are multiples of 100. That is,
• every term beyond 100! is obviously a multiple of 100
• every term beyond 25! contains a factor of both 4 and 25
• every term beyond 10! contains two factors each of both 2 and 5 (i.e. every factorial term contains 4, 5, and 10)
The remaining sum is easy to compute by hand:
7! + 8! + 9! = 7! (1 + 8 + 8 × 9) = 5040 × 81 = 408,240
so the tens digit is 4.
