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Monica [59]
2 years ago
7

For (x) =2x+1 and g(x)= x^2-7, find ( f o g ) (2)

Mathematics
2 answers:
FromTheMoon [43]2 years ago
8 0

Answer:

-5

Step-by-step explanation:

Given functions,

f(x) =2x+1-----(1)

g(x)= x^2-7-----(2)

fog(x)=f(g(x))

=f(x^2-7)           ( From equation (2) )

=2(x^2-7)+1       ( From equation (1) )

=2x^2-14+1

=2x^2-13

Hence,

fog(2) = 2(2)^2-13=8-13=-5

jonny [76]2 years ago
4 0
F(x)=<span>2x+1
</span><span>g(x)= x²-7, 
</span>f o g(x)=2(x²-7)+1=2x²-14+1=2x²-13
f o g(2)=2*2²-13=8-13=-5

or
g(2)=4-7=-3
f o g(2)=2*(-3)+1=-5


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Step-by-step explanation:

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