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2 years ago

7

For (x) =2x+1 and g(x)= x^2-7, find ( f o g ) (2)

2 answers:

FromTheMoon [43]2 years ago

8 0

Answer:

-5

Step-by-step explanation:

Given functions,

$f(x) =2x+1-----(1)$

$g(x)= x^2-7-----(2)$

$fog(x)=f(g(x))$

$=f(x^2-7)$ ( From equation (2) )

$=2(x^2-7)+1$ ( From equation (1) )

$=2x^2-14+1$

$=2x^2-13$

Hence,

$fog(2) = 2(2)^2-13=8-13=-5$

jonny [76]2 years ago

4 0

F(x)=<span>2x+1
</span><span>g(x)= x²-7,
</span>f o g(x)=2(x²-7)+1=2x²-14+1=2x²-13
f o g(2)=2*2²-13=8-13=-5

or
g(2)=4-7=-3
f o g(2)=2*(-3)+1=-5

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