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Monica [59]
3 years ago
7

For (x) =2x+1 and g(x)= x^2-7, find ( f o g ) (2)

Mathematics
2 answers:
FromTheMoon [43]3 years ago
8 0

Answer:

-5

Step-by-step explanation:

Given functions,

f(x) =2x+1-----(1)

g(x)= x^2-7-----(2)

fog(x)=f(g(x))

=f(x^2-7)           ( From equation (2) )

=2(x^2-7)+1       ( From equation (1) )

=2x^2-14+1

=2x^2-13

Hence,

fog(2) = 2(2)^2-13=8-13=-5

jonny [76]3 years ago
4 0
F(x)=<span>2x+1
</span><span>g(x)= x²-7, 
</span>f o g(x)=2(x²-7)+1=2x²-14+1=2x²-13
f o g(2)=2*2²-13=8-13=-5

or
g(2)=4-7=-3
f o g(2)=2*(-3)+1=-5


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Oksana_A [137]

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210

Step-by-step explanation:

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8 0
3 years ago
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ASHA 777 [7]

Answer:

YZ = 44

Step-by-step explanation:

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We can substitute the values we are given to get:

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5 0
2 years ago
If x/8 =5/4 then x=10 true false
galina1969 [7]

Answer:

true

Step-by-step explanation:

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