Answer:
If you go to a website that has a red (or orange) triangle with an exclamation mark next to the link, it's an untrusted site. The things you list (your phone is being attacked and then said something with 26..) are likely to be scam ads (probably viruses). Therefore, I do not recommend you to click the ads or enter that site again.
5x - 2y = -6 ⇒ 10x - 4y = -12
2x - 1y = 1 ⇒ <u>10x - 5y = 5</u>
y = -17
5x - 2(-17) = -6
5x + 34 = -6
<u> - 34 - 34</u>
<u>5x</u> = <u>-40</u>
5 5
x = -8
(x, y) = (-8, -17)
2x + 3y = 432 ⇒ 10x + 15y = 2160
5x + 2y = 16 ⇒ <u>10x + 4y = 32</u>
<u>11y</u> = <u>2128</u>
11 11
y = 193.4545455
2x + 3(193.4545455) = 432
2x + 580.3636364 = 432
<u> - 580.3636364 - 580.3636364</u>
<u>2x</u> = <u>-148.3636364</u>
2 2
x = -74.1818182
(x, y) = (-74.1818184, 193.4545455)
Answer:
C
Step-by-step explanation:
27.034%
Let's define the function P(x) for the probability of getting a parking space exactly x times over a 9 month period. it would be:
P(x) = (0.3^x)(0.7^(9-x))*9!/(x!(9-x)!)
Let me explain the above. The raising of (0.3^x)(0.7^(9-x)) is the probability of getting exactly x successes and 9-x failures. Then we shuffle them in the 9! possible arrangements. But since we can't tell the differences between successes, we divide by the x! different ways of arranging the successes. And since we can't distinguish between the different failures, we divide by the (9-x)! different ways of arranging those failures as well. So P(4) = 0.171532242 meaning that there's a 17.153% chance of getting a parking space exactly 4 times.
Now all we need to do is calculate the sum of P(x) for x ranging from 4 to 9.
So
P(4) = 0.171532242
P(5) = 0.073513818
P(6) = 0.021003948
P(7) = 0.003857868
P(8) = 0.000413343
P(9) = 0.000019683
And
0.171532242 + 0.073513818 + 0.021003948 + 0.003857868 + 0.000413343
+ 0.000019683 = 0.270340902
So the probability of getting a parking space at least four out of the nine months is 27.034%
9514 1404 393
Answer:
6.2
Step-by-step explanation:
We presume your "k-value" is the k in the exponential decay term ...
e^(-kt) . . . where t is the number of time units
This is 1/2 when ...
ln(1/2) = -kt
t = ln(1/2)/(-k) = ln(2)/k
t = 0.69315/0.1124 ≈ 6.2
The half life is about 6.2 time units.
