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kicyunya [14]
3 years ago
14

Study the graph below. Describe the functional relationship between Quantity A and Quantity B. What happens as Quantity A increa

ses?

Mathematics
1 answer:
Alex3 years ago
4 0
There is an inverse corollation between the values of A and B. Specifically, a 3 unit change increase in A results in a 4 unit decrease in B
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If x is a positive integer for how many different values of x is 48/X whole number
Dimas [21]
Factors of 48 : 1,2,3,4,6,8,12,16,24,48....all of these numbers can be subbed in for X to arrive at a whole number....so there are 10 different ways
6 0
3 years ago
Read 2 more answers
448 = -5v + 8(-5 - 7v)<br> What is v?
lapo4ka [179]

Answer:

v = -8

Step-by-step explanation:

First we would have to distribute the 8(-5 - 7v). To do this we would multiply 8 by -5 and 8 by -7v to get 448=-5v-40-56v. After this, we would have to simplify like terms by subtracting 56v from -5v to get 448=-61v-40. We now have to get the variable on one side and to do that, we can add 40 to both sides to get 488=-61v. Finally to get the variable alone, we would have to divide both sides by -61 to get v=-8.

Brainliest would be appreciated!

3 0
2 years ago
Read 2 more answers
Find the value of x and the value of y.
stepladder [879]

Answer:

the 3rst one

Step-by-step explanation:

4 0
3 years ago
10,000 candy canes was divided into 50 boxes. How many candy canes were in each box?​
kumpel [21]

Answer:

200

Step-by-step explanation:

5 0
2 years ago
The probability density function of the time it takes a hematology cell counter to complete a test on a blood sample is f(x)=0.0
uysha [10]

Answer:

a) 20%

b) 40%

c) Mean = 62.5 seconds; Variance = 52.083 seconds

Step-by-step explanation:

The time it takes a hematology cell counter to complete a test on a blood sample is continuously distributed over the period of 50 to 75 seconds with probability f(x) = 0.04.

a) The percentage of tests require more than 70 seconds is:

P(X>70) = 1- \frac{70-50}{75-50} \\P(X>70) =0.2 = 20\%

b)The percentage of tests that require less than one minute (60 seconds) is:

P(X70) =0.4 = 40\%

c) The mean and variance of a continuous distribution are determined by:

M=\frac{A+B}{2}=\frac{50+75}{2}\\ M= 62.5\ seconds\\\\V=\frac{(B-A)^2}{12}=\frac{(75-50)^2}{12}\\  V= 52.083\ seconds

Mean = 62.5 seconds.

Variance = 52.083 seconds.

3 0
3 years ago
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