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cricket20 [7]
3 years ago
13

The circle below is centered at the origin and has a radius of 10. What is its

Mathematics
1 answer:
coldgirl [10]3 years ago
6 0

Answer:

x^2+y^2=100

<u>S</u><u>t</u><u>e</u><u>p</u><u>s</u><u>:</u><u>-</u>

We know Distance formula from origin

\\ \sf\longmapsto \sqrt{x^2+y^2}

Now

\\ \sf\longmapsto \sqrt{x^2+y^2}=10

\\ \sf\longmapsto x^2+y^2=10^2

\\ \sf\longmapsto x^2+y^2=100

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If tñ=2ñ+3, find S10​
Allisa [31]

Answer:

S_{10}=280

Step-by-step explanation:

Given that,

t_n=2n+3 ...(1)

We need to find the value of S_{10}.

Put n = 1 to find the first term.

t_1=2(1)+3=5

Put n = 2 to find the second term.

t_2=2(2)+3=7

Put n = 3 to find the third term.

t_3=2(3)+3=9

Put n = 10 to find the tenth term.

t_{10}=2(10)+3=23

It means we need to find the sum of 5,7,9,.....,23.

The formula for the sum of n terms is given by :

S_=\dfrac{n}{2}(a+a_n)

We have, n = 10, a = 5 and a_n=23

So,

S=\dfrac{10}{2}(5+23)\\\\S_{10}=10\times 28\\\\=280

So, the value of S_{10} is equal to 280.

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3 years ago
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Goshia [24]

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Can anyone give me a geometric sequence will give brainlinest and need sequence of 6
snow_lady [41]

Answer:

3, 6, 9, 12, 15, 18

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If you count by threes you can make a Geometric Sequence of 6.

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user100 [1]

Answer:

x=5+\sqrt{12}

or

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Step-by-step explanation:

x^2-10x+13=0

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(x-5)^2=12

Extract the square root.

x-5=\frac{+}{} \sqrt{12}

Add 5

x=5+\sqrt{12}

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