Answer:
(x, y, z) = (2, -1, 3)
Step-by-step explanation:
I solved it using the elimination method
If we substitute the correct value of x into the right side of the given expression, it should yield 192.
Test x = -8
(-8)^3 + 6(-8)^2 - 40(-8) = 192 Correct
Test x = -4
(-4)^3 + 6(-4)^2 - 40(-4) = 192 Correct
Test x = 6
6^3 + 6(6^2) - 40(6) = 192 Correct
All solutions make sense, so none of them should be eliminated.
Answer:
g=24
Step-by-step explanation:
g/4 -5 = 1
g/4 = 6
g = 24
Steps to solve:
9|9 - 8x| = 2x + 3
~Divide 9 to both sides
|9 - 8x| = 2/9x + 1/3
~Solve absolute value (part one)
|9 - 8x| = 2/9x + 1/3
-74/9x + 9 = 1/3 (Subtracted 2/9x to both sides)
-74/9x = -26/3 (Subtracted 9 to both sides)
x = 39/37 (Multiplied 37/39 to both sides)
~Solve absolute value (part two)
|9 - 8x| = -(2/9x + 1/3)
|9 - 8x| = -2/9x - 1/3 (Distributed negative sign to left side)
-70/9x + 9 = 11/3 (Added 2/9x to both sides)
-70/9x = -28/3 (Subtracted 9 to both sides)
x = 6/5 (Multiplied 9/-70 to both sides)
Therefore, the solutions are x = 39/37 and x = 6/5
Best of Luck!
Answer:
15students per 1 teacher
9 student per 1 tutor.
8 tutors for 72 students
Step-by-step explanation:
From the question, arts academy requires there to be 4 teachers for every 60 students and 3 tutors for every 27 students
✓ 4 teachers for every 60 students
4teacher =60students
Then divide both sides by 4 , i.e (60/4)=15. Which means for every 1 teacher there is 15 students, hence we need 15students per 1 teacher.
✓3 tutors for every 27 students,
3 tutors = 27 students then divide both side by "3" (27/3)= which means we need 9 student per 1 tutor.
How many students does the academy have
per teacher?
15students per 1 teacher
Per tutor?
9 student per 1 tutor.
How many tutors does the academy need if it has 72 students?
Since we need 9 student per 1 tutor., Then to know the numbers of tutor with 72 students,
9 student = 1 tutor.
72 students= X tutor
If we cross multiply we have
72=9X
X=8 tutors
Therefore, we need 8 tutors for 72 students
