Answer:
<h2>Q1. d. 5(x - 4)(x - 6)</h2><h2>Q2. b. (8x - 1)(8x + 1)</h2>
Step-by-step explanation:
There are the combinations that result in a total less than 7 and at least one die showing a 3:
[3, 3] [3,2] [2,1] [1,3] [2,3]
The probability of each of these is 1/6 * 1/6 = 1/36
There is a little ambiguity here about whether or not we should count [3,3] as the problem says "and one die shows a 3." Does this mean that only one die shows a 3 or at least one die shows a 3? Assuming the latter, the total probability is the sum of the individual probabilities:
1/36 + 1/36 + 1/36 + 1/36 + 1/36 = 5/36
Therefore, the required probability is: 5/36
Answer:
Step-by-step explanation:
so u divide 28 by 3 and u get 9 but u have 1 left but if you keep dividing u will get 3 so its 9.33 into infinty
The dot product of the two vectors will be given as follows:
v*w=(-7i+4j)*(-6i+5j)
=(-7*(-6))i+(4*5)j
=-42i+20j
Hence the answer is:
v*w=(-42i+20j)
