1.9.3 Quiz: Absolute Value

Write the equation of a line that is parallel to {y=-\dfrac{5}{4}x+7}y=− 4 5 x+7y, equals, minus, start fraction, 5, divided b

AlladinOne [14]

Write the equation of a line that is parallel to y=-5/4x + 7

Any line parallel to the given line will have the same slope. In an equation presented in the y-intercept form, the slope is always the coefficient of "x". In this case, the slope is -5/4 (meaning the next point is down 5, and 4 to the right).

Our equation so far looks like this: y = -5/4x + b

"b" represents the y-intercept. To solve for be, we will need to substitute values into x and y. The next piece of information it gives us is one of the points, or solutions, of the line. This means that since this point is on the line, we can use its x and y values to substitute.

x = -4

y= 1

y = -5/4x + b

1 = -5/4(-4) + b

1 = 5 + b

-4 = b

Final Answer: y = -(5/4)x -4

7 0

4 years ago

Assume that the probability of a defective computer component is 0.02. Components arerandomly selected. Find the probability tha

solmaris [256]

Answer:

0.0177 = 1.77% probability that the first defect is caused by the seventh component tested.

The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.

Step-by-step explanation:

Assume that the probability of a defective computer component is 0.02. Components are randomly selected. Find the probability that the first defect is caused by the seventh component tested.

First six not defective, each with 0.98 probability.

7th defective, with 0.02 probability. So

$p = (0.98)^6*0.02 = 0.0177$

0.0177 = 1.77% probability that the first defect is caused by the seventh component tested.

Find the expected number and variance of the number of components tested before a defective component is found.

Inverse binomial distribution, with $p = 0.02$

Expected number before 1 defective(n = 1). So

$E = \frac{n}{p} = \frac{1}{0.02} = 50$

Variance is:

$V = \frac{np}{(1-p)^2} = \frac{0.02}{(1-0.02)^2} = 0.0208$

The expected number of components tested before a defective component is found is 50, with a variance of 0.0208.

5 0

3 years ago

here are several types of objects. For each type of object, estimate how many there are in a stack that is 5 feet high. Be prepa

lorasvet [3.4K]

We need to estimate how tall is, on average, one of these object, and then count how many would be in a 5 feet high stack.

For example, on Google you may see that "1.5 cubic foot boxes are the standard box, manufactured by most companies". So, we assume that a standard cardboard box is 1.5 feet tall.

So, if we set the equation

$1.5k = 5 \iff k=\dfrac{5}{1.5}=3.\bar{3}$

So, there would be between 3 and 4 cardboard boxes in a 5 feet tall stack.

Similarly, we can see that the average book is 9 inches tall. 9 inches are 0.75

feet, so we have

$0.75k=5 \iff k=6.\bar{6}$

So, there would be between 6 and 7 books in a 5 feet tall stack.

The average brick is 75 millimeters tall, which means 0.25 feet tall. Again, we have

$0.25k=5 \iff k=20$

So, there would be 20 bricks in a 5 feet tall stack.

Finally, a coin is about 0.006 feet, which leads to

$0.006k=5 \iff k=833.\bar{3}$

So, there would be between 833 and 834 coins in a 5 feet tall stack.

5 0

3 years ago

What is the factor expression of 27 + 33

Nat2105 [25]

20+7 + 30+3 is that what you meAN

3 0

3 years ago

Read 2 more answers

Please help I am stuck on this

9966 [12]

Answer: B. y = 1/2x - 1

Explanation:
I know someone else already answered, but I wanted to explain why the answer is B.

Consider an equation of a line in slope-intercept form: y = mx + b

Since the line intersects the y-axis at -1, that’s the y intercept, or b. We know the slope of the line is positive because it slopes upward from left to right. From each whole number solution point, the line goes up one and two to the right. Slope, represented by m, is “rise” over “run”, or the change in y over the change in x. This makes the slope 1/2.

I hope this helps.

7 0

2 years ago