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otez555 [7]
3 years ago
9

The circumference of a circle is 23π m. What is the area, in square meters? Express your answer in terms of \piπ

Mathematics
1 answer:
LenaWriter [7]3 years ago
6 0

Answer:

Area of the circle =   \frac{529}{4}  π  m²    or      132.25 π  m²

Step-by-step explanation:

To find the area, we will follow the steps below.

First write down the formular for the circumference of a circle, then use the formula to find the radius of the circle after which you can now find the area of the circle.

That is;

C = 2πr

where c is the circumference of the circle and   r is the radius of the circle

From the question given, circumference C = 23π

23π = 2π r

Divide both-side of the equation by 2π

23π/2π  =  2πr/2π

23/2   =  r

radius =   \frac{23}{2}  m

Formula for calculating the area of a circle is given by;

A = πr²

where A= area of the circle   and   r is the radius of the circle

A = π ( \frac{23}{2} )²

A = \frac{529}{4}  π  m²    or      132.25 π  m²

Area of the circle =   \frac{529}{4}  π  m²    or      132.25 π  m²

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Step-by-step explanation:

Given equation is:

x^2=-3x+40

Converting in standard form

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ax^2+bx+c = 0

Here

a = 1

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Quadratic formula is given as:

x = \frac{-b+\sqrt{b^2-4ac}}{2a}\ \ \ \ , \ \ \ \ x = \frac{-b-\sqrt{b^2-4ac}}{2a}

Putting the values of a, b and c

x = \frac{-3+\sqrt{(3)^2-4(1)(-40)}}{2(1)}\ \ \ \ , \ \ \ \ x = \frac{-3-\sqrt{(3)^2-4(1)(-40)}}{2(1)}\\x = \frac{-3+\sqrt{9+160}}{2}\ \ \ \ \ \ \ \ \ \ \ \ \ \ , \ \ \ \ x = \frac{-3-\sqrt{9+160}}{2}\\x = \frac{-3+\sqrt{169}}{2}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ , \ \ \ \ x = \frac{-3-\sqrt{169}}{2}\\x = \frac{-3+13}{2}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ , \ \ \ \ x = \frac{-3-13}{2}\\x = \frac{10}{2}\ \ \ \ \ \ \ \ \ \ \ \ \ , \ \ \ \ x = \frac{-16}{2}\\x = 5\ \ \ \ \ And \ \ \ \ \ \ x = -8

Hence,

The solution is x = 5 and x= -8

Keywords: Quadratic equation, variables

Learn more about quadratic equation at:

  • brainly.com/question/10717746
  • brainly.com/question/10736268

#LearnwithBrainly

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