All categories

3 years ago

Index notation 200 ..........................................

Mathematics

1 answer:

Tju [1.3M]3 years ago

4 0

Answer:

I don't know if you're asking for the product of prime using index notation but I got :

2 × 2 × 2 × 5 × 5

You might be interested in

7x+17=7x-17 is this an identity, conditional or inconsistent equation

miv72 [106K]

7x + 17 = 7x - 17
7x + 17 - 7x = 7x - 17 - 7x
17 = -17

Inconsistent: for no value of x is the above equation true. 17 ≠ -17.

Hope this helps! :)

7 0

3 years ago

Find the length of AD in the figure

Mrac [35]

Find the area of the trapezoid and the shaded area then subtract and u have ur answers

7 0

3 years ago

The graph 4x^2-4x-1 is shown. Use the grpah to find the estimates for the solutions of 4x^2-4x-1=0 and 4x^2 - 4x-1=2

Darina [25.2K]

Answer:

a) The estimates for the solutions of $4\cdot x^{2}-4\cdot x -1 = 0$ are $x_{1}\approx -0.25$ and $x_{2} \approx 1.25$ .

b) The estimates for the solutions of $4\cdot x^{2}-4\cdot x -1 = 2$ are $x_{1}\approx -0.5$ and $x_{2} \approx 1.5$

Step-by-step explanation:

From image we get a graphical representation of the second-order polynomial $y = 4\cdot x^{2}-4\cdot x -1$ , where $x$ is related to the horizontal axis of the Cartesian plane, whereas $y$ is related to the vertical axis of this plane. Now we proceed to estimate the solutions for each case:

a) $4\cdot x^{2}-4\cdot x -1 = 0$

There are two approximate solutions according to the graph, which are marked by red circles in the image attached below:

$x_{1}\approx -0.25$ , $x_{2} \approx 1.25$

b) $4\cdot x^{2}-4\cdot x -1 = 2$

There are two approximate solutions according to the graph, which are marked by red circles in the image attached below:

$x_{1}\approx -0.5$ , $x_{2} \approx 1.5$

5 0

3 years ago

WILL GIVE BRAINEST

Helga [31]

Answer is D. Add the equations in order to solve for the first variable. Plug this value into the other equations in order to solve for th remaining varables

8 0

3 years ago

Read 2 more answers

ITO

Setler [38]

Using the speed - distance relationship, the time left before the appointed time is 27 minutes.

Recall :

Distance = speed × time

Let time = t

At 10mph :

Distance = 10 × (t + 3) = 10t + 30 - - - (1)

At 12 mph :

Distance = 12 × (t - 2) = 12t - 24 - - - - (2)

Equate (1) and (2) :

10t + 30 = 12t - 24

Collect like terms

10t - 12t = - 24 - 30

-2t = - 54

Divide both sides by - 2

t = 54 / 2

t = 27

Hence, the time left before the appointed time is 27 minutes.

Learn more : brainly.com/question/25669152

8 0

2 years ago

Read 2 more answers