Answer:
t = (p^2/mn) - 1/n
Step-by-step explanation:
Here, we want to make t the subject of the formula
we start by equating both sides so as to remove the root
we have this as;
m(t + n)/t = p^2
m(t + n) = tp^2
mt + mn = tp^2
mn = tp^2 - mt
mn = t(p^2-m)
t = (p^2 - m)/mn
t = p^2/mn - 1/n
Answer:380
Step-by-step explanation:
500-120=380
X = 27.5
8x = 220, so 220/8 = 27.5
Answer:
x = 5 and x = -19
Step-by-step explanation:
You're on the right track. It's the "discriminant" that tells you what you want to know here. Before starting, arrange the terms of your quadratic in descending orders of x: 5x^2 + 14x - 19 = 0 (Note that I assumed you meant 14x instead of just 14).
Then the coefficients of this quadratic are a = 5, b = 14 and c = -19.
You are referring to the "quadratic formula." It states this:
-b ± √(b²-4ac)
x = -----------------------
2a
So, we insert the a, b and c values as indicated above:
-14 ± √( 14² - 4[5][-19] ) -14 ± √(196 - 4[5][-19] ) -14 ± √576
x = ----------------------------------- = ---------------------------------- = ----------------------
2(10) 20 20
This comes out to:
x = (-14 + 24) / 2 and x = (-14 - 24) / 2
or:
x = 5 and x = -19
