Answer:

Step-by-step explanation:


As
(g/f)(x) = g(x) / f(x)




Therefore,

<h3><u>Answer</u><u>:</u><u>-</u></h3>
x=17
<h3><u>step-by</u><u>-</u><u>step</u><u> </u><u>Explanation</u><u>:</u><u>-</u></h3>

<h3 />
This is a isosceles triangle. As it is a triangle we can apply sum theory. we have to take the sum of given unknown polynomials as 180° .Then by solving it we can find the value of x.
<h3><u>Solution</u><u>:</u><u>-</u></h3>
Given angles
According to sum theory



- Together like polynomials and constants







I am pretty sure that it is C.
Answer:
H
Step-by-step explanation:
Step 1 of 2: Subtract, sub-step b: Convert mixed number to improper fraction.
Convert mixed number to improper fraction
2 and 1 over 32
1
3
= ( 2 × 3 ) over 3
2 × 3
3
+ 1 over 3
1
3
= ( 6 + 1 ) over 3
6 + 1
3
= 7 over 3
7
3
Step 1 of 2: Subtract, sub-step c: Find common denominator.
Find common denominator
32 over 9
32
9
− 7 over 3
7
3
= ( 32 × 1 ) over ( 9 × 1 )
32 × 1
9 × 1
− ( 7 × 3 ) over ( 3 × 3 )
7 × 3
3 × 3
= 32 over 9
32
9
− 21 over 9
21
9
9 is the least common multiple of denominators 9 and 3. Use it to convert to equivalent fractions with this common denominator.
Step 1 of 2: Subtract, sub-step d: Subtract.
Subtract
32 over 9
32
9
− 21 over 9
21
9
= ( 32 − 21 ) over 9
32 − 21
9
= 11 over 9
11
9
Step 1 of 2: Subtract.
Step 2 of 2: Simplify.
Simplify
11 over 9
11
9
= 1 and 2 over 91
2
9
Domain: 3<x<6
Range: 11<y<8