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GrogVix [38]
3 years ago
15

A box contains 4 black pens and 2 red pens. One pen is chosen at random, and then another pen is chosen at random without replac

ement. What is the probability a black pen was chosen, and then another black pen? *
Mathematics
1 answer:
Serjik [45]3 years ago
7 0

Answer:

Probability is 2/5 or 40%.

Step-by-step explanation:

4/(4+2) = 4/6 = 2/3 first black pen is chosen.

3/5 - second pen is chosen without replacement.

2/3 *3/5= 2/5 - the probability a black pen was chosen, and then another black pen without replacement.

2/5*100 % = 40 %

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Please help me with this
pantera1 [17]

Answer:

  • 8 3/4
  • 2, 3
  • 4 1/2, 11 1/4
  • 9 3/4, 16 1/4
  • Y/B = 2/3

Step-by-step explanation:

<h3>a)</h3>

The first line is simply the sum of the two given numbers.

  3 1/2 +5 1/4 = (3+5) +(2/4+1/4) = 8 3/4

__

To find values on the remaining lines, it is convenient to find the ratios of the numbers involved. The ratio of yellow to blue is ...

  Y/B = (3 1/2)/(5 1/4) = (7/2)/(21/4) = (7/2)(4/21) = 2/3

Then ...

  Y : B : total = 2 : 3 : 5

This tells you the numbers on the second line are ...

  Y = 2; B = 3

__

The value for B on the third line is the basic ratio number multiplied by (6 3/4)/3 = 2 1/4. Then the other two numbers are ...

  Y = 2(2 1/4) = 4 1/2

  total = 5(2 1/4) = 11 1/4

__

The value for Y on the fourth line is the basic ratio number multiplied by (6 1/2)/2 = 3 1/4. Then the other two numbers are ...

  B = 3(3 1/4) = 9 3/4

  total = 5(3 1/4) = 16 1/4

_____

<h3>b)</h3>

The equation is the one we used to find the values on the second line:

  Y/B = 2/3

7 0
2 years ago
PLEASE HELP ASAP) Find the area of this parallelogram
Maurinko [17]
Area = base * altitude = 2 * 2.9 = 5.8 cm^2
6 0
3 years ago
Identify all the prime numbers within each range of numbers given below (inclusive): a. 4 to 11 and b.) 16 to 25
scZoUnD [109]

Answer:

A. 5, 7, 11; B: 17, 19, 23

Step-by-step explanation:

These are all the numbers that don't have common factors besides one and itself

5 star, thank, and brainliest if helpful!

8 0
3 years ago
Can someone pls help, I'll answer your questions if you have any.
Pie
There are no pictures I see you can text me on insta if you need help original_loredo
3 0
3 years ago
Choose one of the factors of 500x3 + 108y18
sammy [17]

Answer:

Option C

Therefore, one of the factors of 500x^3 +108y^\left (18\right ) is (5x+3y^6).

Step-by-step explanation:

Given: 500x^3 +108y^\left (18\right )

the common factor from 500x^3 and 108y^\left (18\right ) is 4.

therefore, 4\cdot \left ( 125x^3+27y^\left (18\right ) \right )

4\cdot \left ( (5x)^3+(3y^6)^3 \right))

Now, use the formula for above expression: (a^3+b^3)=(a+b)(a^2-ab+b^2)

here, a=5x and b=3y^6

( (5x)^3+(3y^6)^3 \right))=(5x+3y^6)(25x^2-15xy^6+9y^12)

Therefore, we have

500x^3 +108y^\left (18\right )=4\cdot (5x+3y^6)\left (25x^2-15xy^6+9y^\left ( 12 \right )  \right )

Therefore, one of the factors of 500x^3 +108y^\left (18\right ) is (5x+3y^6).








7 0
3 years ago
Read 2 more answers
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