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GrogVix [38]
3 years ago
15

A box contains 4 black pens and 2 red pens. One pen is chosen at random, and then another pen is chosen at random without replac

ement. What is the probability a black pen was chosen, and then another black pen? *
Mathematics
1 answer:
Serjik [45]3 years ago
7 0

Answer:

Probability is 2/5 or 40%.

Step-by-step explanation:

4/(4+2) = 4/6 = 2/3 first black pen is chosen.

3/5 - second pen is chosen without replacement.

2/3 *3/5= 2/5 - the probability a black pen was chosen, and then another black pen without replacement.

2/5*100 % = 40 %

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1) The negative exponent rule says that when a base has a negative exponent, flip the base onto the other side of the fraction to make it into a positive exponent. For example, 3^{-2} =
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2) Raising a fraction to a power is the same as separately raising the numerator and denominator to that power. For example, (\frac{3}{4}) ^{3}  =  \frac{ 3^{3} }{4^{3} }.
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Back to the Problem:
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Problem 2
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Answers: 
a = 1
b = </span>\frac{1}{16}<span>
c = </span>\frac{1}{256}
d = 1
e = \frac{4}{9}
f = \frac{16}{81}
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