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Viktor [21]
3 years ago
10

I dont know how to do this question

Mathematics
1 answer:
Inessa05 [86]3 years ago
6 0

9514 1404 393

Answer:

  7 1/3 hours

Step-by-step explanation:

We are to assume that the total number of heater-hours required is a constant. That is, the time is inversely proportional to the number of heaters.

If the number of heaters goes up by a factor of 6/4 = 3/2, then the number of hours will go down by the inverse factor: 2/3.

With 6 heaters instead of 4, the time required is (2/3)(11 hours) = 7 1/3 hours.

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Vedmedyk [2.9K]

\sf \left(\sqrt{2}\right)^3\\\\\\\\\boxed{\sf \mathrm{Apply\:radical\:rule}:\quad \sqrt{a}=a^{\frac{1}{2}}}\\\\\\\\\sf \left(2^{\frac{1}{2}}\right)^3\\\\\\\\\boxed{\sf\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc} }\\\\\\\\\sf \sf 2^{\frac{1}{2}\cdot \:3}\\\\\\\\\sf 2^{\frac{3}{2}}\\\\\\\\\sf 2^{\frac{3}{2}}=2^{1+\frac{1}{2}}\\\\\\\\\sf 2^{1+\frac{1}{2}}\\\\\\\\\boxed{\sf \mathrm{Apply\:exponent\:rule}:\quad \:x^{a+b}=x^ax^b}\\\\\\\\\sf

\sf 2 ^1\cdot \:2^{\frac{1}{2}}\\\\\\\\\boxed{\sf \mathrm{Refine}}\\\\\\\\\boxed{\sf =2\sqrt{2}}

5 0
2 years ago
Rationalize the denominator of 4/14 root 2?
Katarina [22]

First of all, you can simplify the 4 at the numerator and the 14 at the denominator (they're both multiple of 2):

\dfrac{4}{14\sqrt{2}} = \dfrac{2\cdot 2}{2\cdot 7\cdot\sqrt{2}} = \dfrac{2}{7\sqrt{2}}

Now, rationalize a denominator means that you have to get rid of the square root, in order to have an integer denominator.

To do so, remember that you can always multiply any number by 1 without changing its value, and you can always think of 1 as a fraction where numerator and denominator are equal:

\dfrac{2}{7\sqrt{2}} = \dfrac{2}{7\sqrt{2}}\cdot 1 = \dfrac{2}{7\sqrt{2}} \cdot \dfrac{\sqrt{2}}{\sqrt{2}} = \dfrac{2\sqrt{2}}{7\cdot 2} = \dfrac{\sqrt{2}}{7}

5 0
3 years ago
Factoring out the GCF of the polynomial 2x^6+2x^5 will give
telo118 [61]
2x^5(x+1)

hope this helps
5 0
2 years ago
For any perfect square trinomial (quadratic), the constant term (last term) must be positive.
Ronch [10]

Answer:

For the perfect square trinomial (quadratic) i.e. \left(x\:+\:3\right)^2, the constant term (last term) is positive.

Step-by-step explanation:

"Perfect square trinomials" are termed as the quadratics that are the outcomes of squaring binomials.

For example:

\left(x\:+\:3\right)^2

\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a+b\right)^2=a^2+2ab+b^2

a=x,\:\:b=3

=x^2+2x\cdot \:3+3^2

=x^2+6x+9

Therefore, for the perfect square trinomial (quadratic) i.e. \left(x\:+\:3\right)^2, the constant term (last term) is positive.

5 0
3 years ago
When combining like terms what is 8m - 10m?
Bogdan [553]

Answer:

-2m

Step-by-step explanation:

Since the numbers will go below 0 we have to make it in negative numbers

8 0
3 years ago
Read 2 more answers
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