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3 years ago

I dont know how to do this question

Mathematics

1 answer:

Inessa05 [86]3 years ago

6 0

9514 1404 393

Answer:

7 1/3 hours

Step-by-step explanation:

We are to assume that the total number of heater-hours required is a constant. That is, the time is inversely proportional to the number of heaters.

If the number of heaters goes up by a factor of 6/4 = 3/2, then the number of hours will go down by the inverse factor: 2/3.

With 6 heaters instead of 4, the time required is (2/3)(11 hours) = 7 1/3 hours.

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given that<img src="https://tex.z-dn.net/?f=%5Csqrt%7B250%7D%20%3D5%5Csqrt%7B10%7D%20and%20%5Csqrt%7B490%7D%20%3D%207%5Csqrt%7B1

Oksanka [162]

Answer:

√250 - √490

= 5√10 - 7√10

= -2√10

3 0

3 years ago

Translate this sentence into an equation.

vodomira [7]

Answer:

3x-x+2=4

Step-by-step explanation:

4 0

3 years ago

Edward is making a rectangular picture frame. He wants the perimeter of a frame to be no more than 96 inches. He also wants the

Bess [88]

No more than in terms of math means less than or equal to.

P = 2l + 2w

{96 ≤ 2l + 2w

{L ≥ w - 4

Here we see a system of linear inequality in two variables.

You finish.

8 0

3 years ago

The distances from Frisco, Texas to Lincoln, Nebraska is 621 miles. if a driver averages 51.75 miles per hour, approximately wha

True [87]

Givens

D = 621 miles

r = 51.75

t = ?

Formula

d = r * t

Solve

621 miles = 51.75 * t Divide by 51.75

621 / 51.75 = t

t = 12 hours.

Answer B

4 0

3 years ago

Compare the investment below to an investment of the same principal at the same rate compounded annually.

Andrews [41]

$~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$5000\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{semiannually, thus twice} \end{array}\dotfill &2\\ t=years\dotfill &19 \end{cases} \\\\\\ A=5000\left(1+\frac{0.08}{2}\right)^{2\cdot 19}\implies A\approx 22194.067 \\\\[-0.35em] ~\dotfill$

$~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$5000\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &19 \end{cases} \\\\\\ A=5000\left(1+\frac{0.08}{1}\right)^{1\cdot 19}\implies A\approx 21578.505$

6 0

2 years ago