if two of the sides are proportional and the included angles are congruent then the triangles are SIMILAR.
Answer: similar
If the inscribed square has sides of 8in, the diameter of the circle is equal to the diagonal of the square.
d^2=x^2+x^2
d^2=2x^2
d=√(2x^2)
Since d=2r, r=d/2 so
r=(1/2)√(2x^2)
r=√((2x^2)/4)
r=√(x^2/2), since x=8
r=√(64/2)
r=√32
r=√(16*2)
r=4√2 in (exact)
r≈5.66 in (to nearest hundredth of an inch)
Answer:
The answer is B
Step-by-step explanation:
The solution would be like
this for this specific problem:
a + 20 = 5/7 (3a - 20) <span>
a + 20 = (15a - 100)/7 </span><span>
Multiply both side by 7, </span><span>
7a + 140 = 15a - 100 </span><span>
8a = 240<span>
</span></span>a = 30
3a = 90
a + 20 = 50
3a - 20 = 70
<span>5/7 x 70 = 50</span>
