Heat the solvent/solution with the solute over a Bunsen burner whilst mixing it with a glass storing rod or break up the solid into a powder to increase its surface area and then mix it with the solvent/solution.
HCl is <span>limiting reactant, Mg in excess therefore:
</span><span>number of moles HCl:
75.0 mL in liters: 75.0 / 1000 => 0.075 L
Molarity HCl = 1.0 M
n = M x V
n = 1.0 x 0.075
n = 0.075 moles of HCl
</span>Mg(s) + 2 HCl (aq) = H2 (g) + MgCl2 (aq)
<span>2 moles HCl -------------------- 1 mole H2
</span><span>0.075 moles of HCl ------------ ( moles H2)
</span>
moles H2 = 0.075 x 1 / 2
moles H2 = 0.075 / 2
= 0.0375 moles of H2
hope this helps!
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Answer:
3.3765 Mol O2
Explanation:
There is no work for this problem
