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<u>Answer:</u> The percent yield of the reaction is 32.34 %
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
- <u>For benzoic acid:</u>
Given mass of benzoic acid = 3.6 g
Molar mass of benzoic acid = 122.12 g/mol
Putting values in equation 1, we get:
The chemical equation for the reaction of benzoic acid and methanol is:
By Stoichiometry of the reaction
1 mole of benzoic acid produces 1 mole of methyl benzoate
So, 0.0295 moles of benzoic acid will produce = moles of methyl benzoate
- Now, calculating the mass of methyl benzoate from equation 1, we get:
Molar mass of methyl benzoate = 136.15 g/mol
Moles of methyl benzoate = 0.0295 moles
Putting values in equation 1, we get:
- To calculate the percentage yield of methyl benzoate, we use the equation:
Experimental yield of methyl benzoate = 1.3 g
Theoretical yield of methyl benzoate = 4.02 g
Putting values in above equation, we get:
Hence, the percent yield of the reaction is 32.34 %
<u>Answer:</u> The chemical equation is written below.
<u>Explanation:</u>
Every balanced chemical equation follows law of conservation of mass.
This law states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form. This also means that total number of individual atoms on reactant side must be equal to the total number of individual atoms on the product side.
The chemical equation for the reaction of elemental boron and oxygen gas follows:
By Stoichiometry of the reaction:
4 moles of elemental boron reacts with 3 moles of oxygen gas to produce 2 moles of diboron trioxide.
The chemical equation for the reaction of diboron trioxide and water follows:
By Stoichiometry of the reaction:
1 mole of diboron trixoide reacts with 3 moles of water to produce 2 moles of boric acid.
Hence, the chemical equations are written above.