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Ivenika [448]
3 years ago
15

How to get my answer

Mathematics
1 answer:
laila [671]3 years ago
3 0
The answer is 40!!!
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Write two equivalent fractions for 5/10
shtirl [24]
1/2 and 10/20

to get 1/2 you have to divide 5/10 by 5:

  5   /   5          1     
-----          =   ----- 
 10  /   5          2

to get 10/20 you have to multiply 5/10 by 2:

  5   *   2          10
-----           =    ----
 10  *   2          20

Hope it helps! =)
7 0
3 years ago
Read 2 more answers
15 Points!! Is this my teacher's fault? The math and the picture aren't making sense. The blue is my answer.
kogti [31]

Answer:

Your teacher is correct.

Step-by-step explanation:

So first we would have to find what A is equivalent to which is 48. This is because 180 - 132 = 48. Since we know that 132 is a supplementary angle, there has to be another supplementary angle that results in the sum of 180.

With this information in mind, we can create the expression:

2x + 4x + 48 = 180 (A triangle is equal to 180 degrees)

Now simply the equation:

6x + 48 = 180

6x = 132

6x/6 = 132/6

x = 22

Angle C = 44

Angle B = 88

3 0
2 years ago
Algebra 2...can someone tell me how to do this???
crimeas [40]

Use the 2 dots on the line located at (0,1) and (-3,0).


The slope is the change in Y over the change in X:


Change in Y = 0-1 = -1

Change in X = -3 - 0 = -3

Slope = -1 / -3 = 1/3

They intercept in this case is Y1 which = 1.


The equation is y = 1/3x + 1


3 0
3 years ago
HELP! Please! A car is traveling at a rate of 15 meters per second. What is the car's rate in kilometers per hour? How many kilo
gizmo_the_mogwai [7]

Answer:

0.06km

Step-by-step explanation:

15÷1000=0.0015

0.0015×4=0.06

7 0
2 years ago
4. A classmate is having difficulty finding the measures of <BGE and <BDG in the diagram on the right. What mathematical a
Firlakuza [10]
Part 1) Find the measures of angle BGE
we know that
The inscribed angle measures half of the arc it comprises.
so
angle BGE=(1/2)*[arc EB]  

Part 2) Find the angle BDG
we know that
The measure of the external angle is the semi-difference of the arcs that it covers.
so
angle BDG=(1/2)*[arc GEB-arc GB]

8 0
3 years ago
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