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Jet001 [13]
3 years ago
14

△ABC is reflected to form​​ ​ △A′B′C′ ​.

Mathematics
2 answers:
ANTONII [103]3 years ago
7 0
C, Reflection across Y = X
GenaCL600 [577]3 years ago
3 0

Answer:

The correct option is A.

Step-by-step explanation:

The vertices of △ABC are A(−7, 1) , B(−5, −3) , and C(−3, 2) . The vertices of △A′B′C′ are A′(−7, −1) , B′(−5, 3) , and C′(−3, −2) .

The relation between coordinates of preimage and image is defined as

(x,y)\rightarrow (x,-y)

Sign of y-coordinate changes but x-coordinate remains the same. It is possible it the figure is reflection across the x-axis.

Therefore the correct option is A.

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A recipe calls for 2/5 cup of sugar for every 8 teaspoons of vanilla. What is the unit rate in teaspoons per cup ?
tamaranim1 [39]
For 2/5 cup, vanilla needed = 8 teaspoons
so, for 1 cup, it would be: 8 / 2/5
⇒8 × 5/2
⇒40/2
⇒20

In short, Your Answer would be 20 teaspoons

Hope this helps!
7 0
3 years ago
Read 2 more answers
Which expression can be used to find 32% of 130?
Gemiola [76]

Answer:

b. 0.32 • 130

Step-by-step explanation:

Change the percent to decimal form

32% = .32

.32 * 130

6 0
3 years ago
Which is one purpose of cell division?
Lady_Fox [76]
B, because when the organism divides the cells become specialized and continue to divide.
7 0
2 years ago
The lighthouse was moved 230 feet inland at a rate of 40 feet per hour. How many hours did it take to move the lighthouse? What
Aleks04 [339]

Answer:

5.75

Step-by-step explanation:

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3 0
3 years ago
Can we obtain a diagonal matrix by multiplying two non-diagonal matrices? give an example
polet [3.4K]
Yes, we can obtain a diagonal matrix by multiplying two non diagonal matrix.

Consider the matrix multiplication below

\left[\begin{array}{cc}a&b\\c&d\end{array}\right]   \left[\begin{array}{cc}e&f\\g&h\end{array}\right] =  \left[\begin{array}{cc}a e+b g&a f+b h\\c e+d g&c f+d h\end{array}\right]

For the product to be a diagonal matrix,

a f + b h = 0 ⇒ a f = -b h
and c e + d g = 0 ⇒ c e = -d g

Consider the following sets of values

a=1, \ \ b=2, \ \ c=3, \ \ d = 4, \ \ e=\frac{1}{3}, \ \ f=-1, \ \ g=-\frac{1}{4}, \ \ h=\frac{1}{2}

The the matrix product becomes:

\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}\frac{1}{3}&-1\\-\frac{1}{4}&\frac{1}{2}\end{array}\right] = \left[\begin{array}{cc}\frac{1}{3}-\frac{1}{2}&-1+1\\1-1&-3+2\end{array}\right]= \left[\begin{array}{cc}-\frac{1}{6}&0\\0&-1\end{array}\right]

Thus, as can be seen we can obtain a diagonal matrix that is a product of non diagonal matrices.
8 0
3 years ago
Read 2 more answers
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