I WILL WORSHIP U PLS WHATS THE ANSWER

Mathematics

2 answers:

victus00 [196]3 years ago

6 0

Huh what is it I cant see

mart [117]3 years ago

3 0

Answer:

A. is not true

Step-by-step explanation:

$\angle{BCA}$ appears to be acute, and $\angle{BCD}$ appears to be its obtuse supplement.

Just to be sure the diagram isn't lying to you, set this up:

4x + 9 + (9x - 11) = 180

13x - 2 = 180

13x = 182

x = 14

$m\angle{BCA}=65^\circ\\m\angle{BCD}=115^\circ$

Those two angles are <u>not</u> congruent.

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1/3 of a number represented as n

slamgirl [31]

N/3 if thats what your looking for

3 0

4 years ago

1500 soldiers arrive at a training camp. A few soldiers desert the camp. The drill sergeants divide the remaining soldiers into

iren [92.7K]

Answer:

The number of deserters is 34.

Step-by-step explanation:

We have to calculate the number of desertors in a group of 1500 soldiers.

The sergeant divides in groups of different numbers and count the lefts over.

If he divide in groups of 5, he has on left over. The amount of soldiers grouped has to end in 5 or 0, so the total amount of soldiers has to end in 1 or 6.

If he divide in groups of 7, there are three left over. If we take 3, the number of soldiers gruoped in 7 has to end in 8 or 3. The only numbers bigger than 1400 that end in 8 or 3 and have 7 as common divider are 1428 and 1463.

If we add the 3 soldiers left over, we have 1431 and 1466 as the only possible amount of soldiers applying to the two conditions stated until now.

If he divide in groups of 11, there are three left over. We can test with the 2 numbers we stay:

$(1431-3)/11=1428/11=129.82\\\\(1466-3)/11=1463/11=133$