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DiKsa [7]
3 years ago
8

A toy rocket is launched straight up into the air with an initial velocity of 60 ft/s from a table 3 ft above the ground. If acc

eleration due to gravity is –16 ft/s2, approximately how many seconds after the launch will the toy rocket reach the ground? h(t) = at2 + vt + h0 0.05 s 2.03 s 3.80 s 3.70 s
Mathematics
1 answer:
alexdok [17]3 years ago
3 0
The equation is:
h ( t ) = - 16 t² + 60 t + 3
The toy rocket will reach the ground when: h ( t ) = 0
- 16 t² + 60 t + 3 = 0
t _{12} =  \frac{-60+/- \sqrt{3600+192} }{-32}
t 1 = - 0.05
t 2 = 3.8
Answer:
C ) 3.80 s

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