Ask question

Ask question

All categories

4 years ago

8

after taking nine test Carols average grade in her Italian classes 90 her teacher drops the lowest of the nine test scores to de

termine the final grade of Carols final grade is 91 what was her lowest test score

1 answer:

Ostrovityanka [42]4 years ago

5 0

Answer:

82

Step-by-step explanation:

The sum of scores for the 9 tests must be 90 * 9 = 810. The sum of scores for the 8 tests is 8 * 91 = 728 so the lowest score is 810 - 728 = 82.

You might be interested in

The differece of twice <br> a number and five is<br> three. Find the number

Anton [14]

Answer:

Step-by-step explanation:

LEt the number be x.

2x - 5 = 3

2x = 3 + 5 = 8

x = 8/2 = 4

To solve the equation: add 5 to both sides and then multiply by 1/2.

5 0

3 years ago

Read 2 more answers

The first term of a sequence is a multiple of 3 The second term of this sequence is 6 less than the first term. The third term i

Mekhanik [1.2K]

Answer:

First term $= 15$

Second term $= 9$

Third term $= 3$

Step-by-step explanation:

Given,

First term $= 3x$

Second term $= 3x - 6$

Third term $= \frac{1}{5} (3x) = \frac{3x}{5}$

Also,

$3x - \frac{3x}{5} = 12$

$\frac{15x}{5} - \frac{3x}{5} = 12$

$\frac{15x - 3x}{5} = 12$

$15x - 3x = 12 \times 5$

$12x = 60$

$x = \frac{60}{12}$

$x = 5$

With the value of $x$ , we conclude that the first three terms are as follows:

First term $= 3x = 3×5 = 15$

Second term $= 3x - 6 = 15 - 6 = 9$

Third term $= \frac{3x}{5} =\frac{15}{5}= 3$

7 0

2 years ago

Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 24 students, she finds 2 w

irina1246 [14]

Answer:

A 95% confidence interval for the proportion of students who eat cauliflower on Jane's campus is [0.012, 0.270].

Step-by-step explanation:

We are given that Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 24 students, she finds 2 who eat cauliflower.

Firstly, the pivotal quantity for finding the confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of students who eat cauliflower

n = sample of students

p = population proportion of students who eat cauliflower

<em>Here for constructing a 95% confidence interval we have used a One-sample z-test for proportions.</em>

<u>So, 95% confidence interval for the population proportion, p is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

Now, in Agresti and Coull's method; the sample size and the sample proportion is calculated as;

$n = n + Z^{2}__(\frac{_\alpha}{2})$

n = $24 + 1.96^{2}$ = 27.842

$\hat p = \frac{x+\frac{Z^{2}__(\frac{\alpha}{2}_) }{2} }{n}$ = $\hat p = \frac{2+\frac{1.96^{2} }{2} }{27.842}$ = 0.141

<u>95% confidence interval for p</u> = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.141 -1.96 \times {\sqrt{\frac{0.141(1-0.141)}{27.842} } }$ , $0.141 +1.96 \times {\sqrt{\frac{0.141(1-0.141)}{27.842} } }$ ]

= [0.012, 0.270]

Therefore, a 95% confidence interval for the proportion of students who eat cauliflower on Jane's campus [0.012, 0.270].

The interpretation of the above confidence interval is that we are 95% confident that the proportion of students who eat cauliflower on Jane's campus is between 0.012 and 0.270.

7 0

3 years ago

Which equation has a graph that is a parabola with a vertex at (5, 3)?

frozen [14]

Answer: The equation that has a graph which is a parabola with a vertex at (5, 3) would be y = (x – 5)^2 + 3. The general form of a parabola which the vertex is not in the origin is expressed as y = a(x - h)^2 + k where (h,k) represents the vertex.

8 0

3 years ago

For a given input value b, the function f outputs a value a to satisfy the following equation. 4a+7b=−52 Write a formula for ) f

Sergio [31]

Answer: Our required formula becomes :

$a=f(b)=-13-\frac{7}{4}b$

Step-by-step explanation:

Since we have given that

$4a+7b=-52\\$

We need to write a formula for f(b) in terms of b So, it becomes

$4a=-52-7b\\\\a=\frac{-52-7b}{4}\\\\a=\frac{-52}{4}-\frac{7b}{4}\\\\a=-13-\frac{7b}{4}$

Hence, our required formula becomes :

$a=f(b)=-13-\frac{7}{4}b$

5 0

3 years ago

Read 2 more answers