Answer:
x = 15
Step-by-step explanation:
Pytago: a^2 + b^2 = c^2
x = 
= 15
State the vertex and axis of symmetry of the graph of y=ax^2+c
General form of quadratic equation is 
There is no bx in our given equation, so we put 0x
Given equation can be written as 
a=a , b=0
Now we use formula to find vertex
Now we plug in 0 for 'a' and find out y
So our vertex is (0,c)
The axis of symmetry at x coordinate of vertex
So x=0 is our axis of symmetry
Answer:
(-2, -9)
explanation:
original coordinates of B: (7, 9)
use the formula: (x, y) ---> (x, -y)
- if reflects over x-axis new coordinates: (7, -9)
If horizontally shifted there will be change in x axis,
- new coordinates (7-9,-9) → (-2, -9)
6/12 or 1/2
normal-first one
simplify-second one
hope it helps :)
Answer:
See below.
Step-by-step explanation:
ax^2 + bx + c = 0
a(x^2 + b/a x) + c = 0
Completing the square:
a [ (x + b/2a)^2 - b^2/4a^2] + c = 0
a[ (x + b/2a )]^2 - b^2 / 4a + c = 0
a[ (x + b/2a )]^2 = b^2 / 4a - c
Dividing both sides by a:
(x + b/2a )^2 = b^2/4a^2 - c/a
Taking square roots of both sides:
x + b/2a = +/- √ (b^2/ 4a^2 - c/a)
x + b/2a = +/- √ [ ( b^2 - 4ac) / 4a^2 )]
x + b/2a = +/- √ ( b^2 - 4ac) / 2a
Subtracting b/2a from both sides and converting the right side to one fraction:
x = [- b +/- √ ( b^2 - 4ac] / 2a.
