All categories

2 years ago

Finding the area of a regular polygon

Mathematics

1 answer:

ddd [48]2 years ago

5 0

<h2>Solution:</h2>

360° ÷ 10 ÷ 2 = 18°

So the length of the decagon side is:

10 × tan18° × 2 = 20 × tan18°

The area is: ½ × 20 × tan18° × 10 × 10 = 1000 × tan18°

≈ 324.9

.: 324.9 is the final answer.

I hope this helps. 

You might be interested in

Please help me solve this!!

horsena [70]

Answer: 18

Step-by-step explanation: Simplify 2^3 to 8. 3/4 (8+4^2). Simplify 4^2 to 16. 3/4 (8+16). Simplify 8+10 to 24. 3/4*24. Use this rule: a/b * c = ac/b. Simplify 3*24 to 72. 72/4.

Hope this helps!

8 0

3 years ago

What is 65 5/6+ 6 4/6 in simplest form?

juin [17]

72.5 as decimal or 72 1/2 as fraction

8 0

4 years ago

What is the equation, in point-slope form, of the line

mixas84 [53]

Answer:

y=-1x-1

Step-by-step explanation:

it should be this

3 0

3 years ago

Using the laws of indices simplify 625^3/8 ×5^1/2÷ 25

Oxana [17]

Answer:

Step-by-step explanation:

$\huge {625}^{ \frac{3}{8} } \times {5}^{ \frac{1}{2} } \div 25 \\ \\ = \huge {( {5}^{4})}^{ \frac{3}{8} } \times {5}^{ \frac{1}{2} } \div {5}^{2} \\ \\ = \huge{5}^{ \cancel4 \times \frac{3}{ \cancel8 \: \: \red{ \bold 2}} } \times {5}^{ \frac{1}{2} } \div {5}^{2} \\ \\ \huge= {5}^{ \frac{3}{2} } \times {5}^{ \frac{1}{2} } \div {5}^{2} \\ \\ \huge= {5}^{ \frac{3}{2} + \frac{1}{2}} \div {5}^{2} \\ \\ \huge= {5}^{ \frac{4}{2} } \div {5}^{2} \\ \\ \huge= {5}^{ 2 } \div {5}^{2} \\ \\ \huge= {5}^{ 2 - 2 } \\ \\ \huge= {5}^{ 0 } \\ \\ \huge= 1$

5 0

3 years ago

What type of number cannot be written as a fraction p/q, where p and q are integers and q is not equal to zero

Schach [20]

That is the definition of a irrational number, A rational number must be able to be written as a ratio of 2 integers. The denominator cannot be 0, because that would make the number undefined

8 0

3 years ago

Read 2 more answers

Finding the area of a regular polygon​

Finding the area of a regular polygon