2cos2x=y
dy/dx(2cos2x)=-4sin2x
d/du cosu= u'×cos'u=-u'×sinu
d/du sinu= u'×sin'u= u'×cosu
d/du tanu = u'×(1+tan²u)
d/du cotu = u'×-(1+cot²u)
proof for cosu :
cos2x= 1-2sin²x
or 2cosx²-1
or cos²x-sin²x
we will one of this fro example let's take the first one
d/dx 1-2sin²x=0-2×2(sinx)×cosx=-2sin2x
and we have 2 in the begining so its -4sin2x
Answer:
210
Step-by-step explanation:
add 30 with 60 multiplied by 3
Answer:
12
Step-by-step explanation:
f(x) = -x^3 + x^2
Let x = -2
Evaluate the expression
f(-2) = -(-2)^3 + (-2)^2
= - (-2)*(-2) * (-2) + ( -2) * (-2)
= -(-8) + ( 4)
= 8 + 4
= 12
9514 1404 393
Answer:
3
Step-by-step explanation:
Let x represent the number. The problem statement tells you ...
2/3(3x +6) = 10
2x +4 = 10 . . . . . . use the distributive property
x +2 = 5 . . . . . . . . divide by 2
x = 3 . . . . . . . . . . .subtract 3
The number is 3.
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<em>Comment on the solution</em>
The above shows an "alternative" solution method. The more usual way this might be done is ...
2(3x +6) = 30 . . . . . multiply by 3 to clear fractions
6x +12 = 30 . . . . . . . eliminate parentheses
6x = 18 . . . . . . . . . . . subtract 12
x = 3 . . . . . . . . . . . . divide by 6
I believe the answer is 6
