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kondor19780726 [428]
3 years ago
12

25% of a university's freshman class are majoring in Engineering. If 500 students in the freshman class are Engineering majors,

how many students are in the freshman class?
Mathematics
1 answer:
Pepsi [2]3 years ago
4 0

Answer:

2000

Step-by-step explanation:

100/25=4

500*4=2000

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Step-by-step explanation:

btw the answer is

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5 0
3 years ago
It costs Charlie's Car Repair Shop $27 to change the oil. The shop charges their costumers $40 for an oil change. What is the pe
frosja888 [35]
Cost Price for oil change =$27 
Charge for the customers =$40 
Markup cost = Difference between selling price and cost price =$40-$27=$13  
To find the percent of markup, divide the markup cost by the cost price and multiply it by 100. 
Markup percent = (13/27)*100 
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3 0
2 years ago
Please help me with my homework<br><br> <img src="https://tex.z-dn.net/?f=%5Cbf%7B%28x%2B9%29%5E5%7D" id="TexFormula1" title="\b
Brut [27]

Answer:

x⁵+ 45x⁴+ 810x³+ 7290x²+ 32805x +59049

Step-by-step explanation:

Greetings !

Given expression

(x + 9) {}^{5}

write 5 as a sum

(x + 9) {}^{3 + 2}

use \: a {}^{m + n}  = a {}^{m}  \times a {}^{n} to \: expand \: the \: expression.

(x + 9) {}^{3}  \times (x + 9) {}^{2}

Use (a+b)³=a³+3a²b+b³ to expand the expression

(x {}^{3}  + 27x {}^{2}  + 243x + 729) \times (x + 9) {}^{2}

Use (a+b)²=a²+2ab+b² to the second expression to expand it

(x {}^{3}  + 27x {}^{2}  + 243x + 729) \times(x {}^{2}  + 18x + 81)

Finally, simplify the expression gives

x {}^{5}  + 45x {}^{4}  + 810x {}^{3}  + 7290x {}^{2}  + 32805x + 59049

Hope it helps!

3 0
2 years ago
Read 2 more answers
What is the value of x in the equation 8x – 2y = 48, when y = 4?<br> 6<br> ОО<br> 7<br> O 14<br> 48
Otrada [13]
The value of x is 7........
6 0
2 years ago
99 POINT QUESTION, AND BRAINLIEST!!!
77julia77 [94]
\displaystyle\int_{x=1}^{x=14}\frac{1-\cos4x}{4x-\sin4x}\,\mathrm dx

First, replace y=4x and \mathrm du=4\,\mathrm dx. Then you have

\displaystyle\frac14\int_{y=4}^{y=56}\frac{1-\cos y}{y-\sin y}\,\mathrm dy

If we take z=y-\sin y, then immediately we see a differential in the numerator in the form of \mathrm dz=(1-\cos y)\,\mathrm dy. So the integral becomes

\displaystyle\frac14\int_{z=4-\sin4}^{z=56-\sin56}\frac{\mathrm dz}z

and evaluates to

\dfrac14\ln|z|\bigg|_{z=4-\sin4}^{z=56-\sin56}=\dfrac14\left(\ln|56-\sin56|-\ln|4-\sin4|\right)=\dfrac14\ln\left|\dfrac{56-\sin56}{4-\sin4}\right|

making (A) the correct answer.
4 0
2 years ago
Read 2 more answers
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