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2 years ago

If the rejection region is +1.10, what will be your decision if the z computed value is 2.34

Mathematics

1 answer:

IRINA_888 [86]2 years ago

7 0

The decision when the z value is within the rejection region is that we'll have to reject the null hypothesis.

<h3>What is a rejection region?</h3>

It should be noted that the rejection region is also known as the critical region. It is the set of values where the null hypothesis is rejected.

When the observed test statistic is in the rejection region, we'll have to reject the null hypothesis and then accept rte alternative hypothesis.

Learn more about z scores on:

brainly.com/question/6096474

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PLEASE HELP Complete the table with the number of sit-ups you have to do sunday so that the mean number of sit-ups per day is 10

klemol [59]

The complete table will be:

$Monday - 100\\ Tuesday-65\\ Wednesday- 120\\ Thursday-150\\ Friday-90\\ Saturday- 0\\ Sunday-175$

<u><em>Explanation</em></u>

Suppose, the number of sit-ups in Sunday is $x$

Mean is the simple average of some numbers. <u>For finding the mean number</u> of sit-ups per day, we need to <u>divide the 'total number of sit-ups' by the 'total number of days'</u>.

Here the total number of days is 7 and the total number of sit-ups for 7 days $= 100+65+120+150+90+0+x= 525+x$

Given that, the mean number of sit-ups per day is 100. So, the equation will be...

$\frac{525+x}{7}=100\\ \\ 525+x=700\\ \\ x= 700-525=175$

So, the number of sit-ups you have to do Sunday is 175.

6 0

4 years ago

Please help solve this

White raven [17]

Answer:

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CBA=CDA (altanate angles BC=AD)

C=A (altanate angles (BC=AD)

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brainyliest please

8 0

3 years ago

The radius of a circle measures 5 inches A central angle of the circle measuring 12 radians cuts off a sector

blagie [28]

Answer:

25/4 square inches

Step-by-step explanation:

The area of a sector of a circle is given by the formula ...

A = (1/2)r²θ

where r is the radius and θ is the central angle in radians.

For your sector, the area is ...

A = (1/2)(5 in)²(1/2) = 25/4 in²

8 0

3 years ago

Which of the following transformations<br> carry this regular polygon onto itself?

PolarNik [594]

Answer:

Reflection across L.

5 0

3 years ago

Suppose quantity s is a length and quantity t is a time. Suppose the quantities v and a are defined by v = ds/dt and a = dv/dt.

finlep [7]

Answer:

a) $v = \frac{[L]}{[T]} = LT^{-1}$

b) $a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

c) $\int v dt = s(t) = [L]=L$

d) $\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

e) $\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

Step-by-step explanation:

Let define some notation:

[L]= represent longitude , [T] =represent time

And we have defined:

s(t) a position function

$v = \frac{ds}{dt}$

$a= \frac{dv}{dt}$

Part a

If we do the dimensional analysis for v we got:

$v = \frac{[L]}{[T]} = LT^{-1}$

Part b

For the acceleration we can use the result obtained from part a and we got:

$a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

Part c

From definition if we do the integral of the velocity respect to t we got the position:

$\int v dt = s(t)$

And the dimensional analysis for the position is:

$\int v dt = s(t) = [L]=L$

Part d

The integral for the acceleration respect to the time is the velocity:

$\int a dt = v(t)$

And the dimensional analysis for the position is:

$\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

Part e

If we take the derivate respect to the acceleration and we want to find the dimensional analysis for this case we got:

$\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

7 0

3 years ago