Answer:
C) Fail to reject the claim that the mean temperature is equal to 43°F when it is actually different from 43°F.
Options:
A) Fail to reject the claim that the mean temperature is equal to 43°F when it is actually 43°F.
B) Reject the claim that the mean temperature is equal to 43°F when it is actually 43°F.
C) Fail to reject the claim that the mean temperature is equal to 43°F when it is actually different from 43°F.
D) Reject the claim that the mean temperature is equal to 43°F when it is actually different from 43°F.
Explanation:
The null hypothesis H0: µ=43°F (a true mean temperature maintained by refrigerator is equal to 43°)
The alternative hypothesis Ha: µ<>43 (a true mean temperature maintained by refrigerator is not equal to 43).
A type II error does not reject null hypothesis H0 when it is false. Therefore, the type II error for the test fails to reject the claim that the mean temperature is equal to 43°F when it is actually different from 43°F.
12 2/3 servings can be prepared
you divide 6 1/3 and 1/2
<span>|5x + 10| = 10.............</span>
97.07%
Step-by-step explanation:
total number of students is
696+21=717
696/717×100=97.07
answer is 97.07%
You must find the least common multiple of 8, 5, and 10. In this case the least common denominator is 40. 8•5= 40, 5•8= 40, and 10•4= 40. Answer: 40.