Answer:
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Algebra Examples
Popular Problems Algebra Solve by Substitution 3x-4y=9 , -3x+2y=9
3
x
−
4
y
=
9
,
−
3
x
+
2
y
=
9
Solve for
x
in the first equation.
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x
=
3
+
4
y
3
−
3
x
+
2
y
=
9
Replace all occurrences of
x
in
−
3
x
+
2
y
=
9
with
3
+
4
y
3
.
x
=
3
+
4
y
3
−
3
(
3
+
4
y
3
)
+
2
y
=
9
Simplify
−
3
(
3
+
4
y
3
)
+
2
y
.
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x
=
3
+
4
y
3
−
9
−
2
y
=
9
Solve for
y
in the second equation.
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Move all terms not containing
y
to the right side of the equation.
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x
=
3
+
4
y
3
−
2
y
=
18
Divide each term by
−
2
and simplify.
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x
=
3
+
4
y
3
y
=
−
9
Replace all occurrences of
y
in
x
=
3
+
4
y
3
with
−
9
.
x
=
3
+
4
(
−
9
)
3
y
=
−
9
Simplify
3
+
4
(
−
9
)
3
.
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x
=
−
9
y
=
−
9
The solution to the system of equations can be represented as a point.
(
−
9
,
−
9
)
The result can be shown in multiple forms.
Point Form:
(
−
9
,
−
9
)
Equation Form:
x
=
−
9
,
y
=
−
9
image of graph
Answer: 32
Step-by-step explanation:
we have in this case right triangle with a leg equal to 24 and a hypotenuse equal to 40
c^2=a^2+b^2
40^2=24^2+b^2
b^2=1600-576=1024
b=sqrt1024=32
12. the change in temperature is -1 C. -3 C + -1 C= -4 C
13. The net gain. Lin gained 14 yards, then loss 7 yards, and lastly gained 9 yards
14 + (-7) + 9= 16 yards
14. Pythagoras was born 582 BC. Newton 1643 AD
1643-582= 1,061 years
15. Sonny has $75 but he needs to buy something costs $93
he needs to borrow $18.
93-75= $18
The absolute value of a number can never be negative. That's because it represents the distance of a number from zero on a number line. The number

is

digits to the left of zero on a number line. So, the absolute value of

would be

.
Let me know if you have any questions regarding this problem!
Thanks!
-TetraFish
Answer:
Step-by-step explanation:
Here are the steps to follow when solving absolute value inequalities:
Isolate the absolute value expression on the left side of the inequality.
If the number on the other side of the inequality sign is negative, your equation either has no solution or all real numbers as solutions.
If your problem has a greater than sign (your problem now says that an absolute value is greater than a number), then set up an "or" compound inequality that looks like this:
(quantity inside absolute value) < -(number on other side)
OR
(quantity inside absolute value) > (number on other side)
The same setup is used for a ³ sign.
If your absolute value is less than a number, then set up a three-part compound inequality that looks like this:
-(number on other side) < (quantity inside absolute value) < (number on other side)
The same setup is used for a £ sign