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3 years ago

Write the following using algebraic notation, using the letter x for any

Mathematics

1 answer:

Alona [7]3 years ago

3 0

Answer:

(x+7)÷5

Step-by-step explanation:

since the number is unknown, it becomes X. Because we first add 7 then divide by 5, the expression will be a bracketed (X+7), followed by the division by 5. This makes sense because of the BODMAS rule to which, in coherence with the BODMAS rule, we first solve the expression in the brackets then move on outside them.

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According to his car odometer,Alfonso drove a total of 10 kilometers from his house to the movie theater and back again approxim

Brums [2.3K]

Answer:

It is approximately 3.10 miles from Alfonso's house to the movie theater

Step-by-step explanation:

First, identify what you know:

1) Alfonso drove from his house TO the movie theater, and then BACK to his house.

2) Alfonso's odometer shows him that the ENTIRE trip was 10 miles.

If the entire trip was 10 miles, and he only went to the move theater, AND took the same route back, then we simply divide 10 in half! This will give us the distance from his house the the movie theater, or rather, half of the trip, in kilometers.

10/2 = 5 kilometers.

Now, what is 5 kilometers in miles? Well, one mile is equal to 1.60934 kilometers, and one kilometer is equal to 0.621371 miles. So, simply multiply!

5 km x 0.621371 miles = 3.106855

The approximate distance from his house to the theater is 3.10 miles!

Hope this helps! :)

3 0

3 years ago

Nancy has a bank account that has a balance of $320 and allows for a maximum of 6 deposits per month. She has decided that each

LenaWriter [7]

Answer: 320,340,360,380,400,420,440

6 0

2 years ago

Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution. At Meadowbrook Hospital, the mean we

Marina86 [1]

Answer:

Required Probability = 0.1283 .

Step-by-step explanation:

We are given that at Meadow brook Hospital, the mean weight of babies born to full-term pregnancies is 7 lbs with a standard deviation of 14 oz.

Firstly, standard deviation in lbs = 14 ÷ 16 = 0.875 lbs.

Also, Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution.

Let X = mean weight of the babies, so X ~ N( $\mu = 7 lbs , \sigma^{2} = 0.875^{2} lbs$ )

The standard normal z distribution is given by;

Z = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, X bar = sample mean weight

n = sample size = 4

Now, probability that the average weight of the four babies will be more than 7.5 lbs = P(X bar > 7.5 lbs)

P(X bar > 7.5) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ > $\frac{7.5-7}{\frac{0.875}{\sqrt{4} } }$ ) = P(Z > 1.1428) = 0.1283 (using z% table)

Therefore, the probability that the average weight of the four babies will be more than 7.5 lbs is 0.1283 .

8 0

3 years ago

Given sin x = -4/5 and x is in quadrant 3, what is the value of tan x/2

love history [14]

bearing in mind that, on the III Quadrant, sine as well as cosine are both negative, and that hypotenuse is never negative, so, if the sine is -4/5, the negative number must be the numerator, so sin(x) = (-4)/5.

$\bf sin(x)=\cfrac{\stackrel{opposite}{-4}}{\stackrel{hypotenuse}{5}}\impliedby \textit{let's find the \underline{adjacent}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{5^2-(-4)^2}=a\implies \pm\sqrt{9}=a\implies \pm 3=a \\\\\\ \stackrel{III~Quadrant}{-3=a}~\hfill cos(x)=\cfrac{\stackrel{adjacent}{-3}}{\stackrel{hypotenuse}{5}} \\\\[-0.35em] ~\dotfill$

$\bf tan\left(\cfrac{\theta}{2}\right)= \begin{cases} \pm \sqrt{\cfrac{1-cos(\theta)}{1+cos(\theta)}} \\\\ \cfrac{sin(\theta)}{1+cos(\theta)}\qquad \leftarrow \textit{let's use this one} \\\\ \cfrac{1-cos(\theta)}{sin(\theta)} \end{cases} \\\\[-0.35em] ~\dotfill$

$\bf tan\left( \cfrac{x}{2} \right)=\cfrac{~~\frac{-4}{5}~~}{1-\frac{3}{5}}\implies tan\left( \cfrac{x}{2} \right)=\cfrac{~~\frac{-4}{5}~~}{\frac{2}{5}}\implies tan\left( \cfrac{x}{2} \right)=\cfrac{-4}{5}\cdot \cfrac{5}{2} \\\\\\ tan\left( \cfrac{x}{2} \right)=\cfrac{-4}{2}\cdot \cfrac{5}{5}\implies tan\left( \cfrac{x}{2} \right)=-2$

4 0

3 years ago

Read 2 more answers

Round 258,494 to the nearest ten-thousand.

Lorico [155]

Answer:

260,000

Step-by-step explanation:

the 5 turns to a 6 because the 8 is bigger than 5

3 0

3 years ago