All categories

3 years ago

Write the following using algebraic notation, using the letter x for any

Mathematics

1 answer:

Alona [7]3 years ago

3 0

Answer:

(x+7)÷5

Step-by-step explanation:

since the number is unknown, it becomes X. Because we first add 7 then divide by 5, the expression will be a bracketed (X+7), followed by the division by 5. This makes sense because of the BODMAS rule to which, in coherence with the BODMAS rule, we first solve the expression in the brackets then move on outside them.

You might be interested in

What function equation is represented by the graph?

kupik [55]

the answer would be ...

f(x) = -5/2x + 4

We know this because the constant in this equation, 4, is the y-intercept!

This means that the number without the variable is where the line intersects the y-axis.

Additionally, the slope is called the "rise over run", but in this case it is negative. At the point, 4, on the y-axis, we go down 5 units (the numerator of the slope) and to the right by 2 units (the denominator).

We find ourselves at where the line intercepts the x-axis!

I hope my explanation isn't confusing and that it is helpful! If you have any questions or concerns, message me! :)

8 0

3 years ago

Four cards are dealt from a standard fifty-two-card poker deck. What is the probability that all four are aces given that at lea

elena-s [515]

Answer:

The probability is 0.0052

Step-by-step explanation:

Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:

P(A/B) = P(A∩B)/P(B)

The probability P(B) that at least three are aces is the sum of the following probabilities:

The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725

There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

$nCk=\frac{n!}{k!(n-k)!}$

So, the number of ways to select exactly 3 aces is:

$4C3*48C1=\frac{4!}{3!(4-3)!}*\frac{48!}{1!(48-1)!}=192$

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725

Then, the probability P(B) that at least three are aces is:

$P(B)=\frac{1}{270,725} +\frac{192}{270,725} =\frac{193}{270,725}$

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:

P(A∩B) = 1/270,725

Finally, the probability P(A/B) that all four are aces given that at least three are aces is:

$P=\frac{1/270,725}{193/270,725} =\frac{1}{193}=0.0052$

5 0

3 years ago

How to do this question plz

sergeinik [125]

Answer:

The answer is yes.

Step-by-step explanation:

All you have to do is substitute the y, which is 5, and the x, which is 2, into the equation. When you solve it the answer in the end will be 5=5, which means that point (2,5) does line on that line.

3 0

3 years ago

Describe the number of faces and thier shapes

Marysya12 [62]

Do you have pictures

3 0

3 years ago

A soccer team made 76 penalty shots out of 100.Which ratio represents successful penalty shots to missed penalty shots?

almond37 [142]

Sense we are wanting to find how many were miss, then, we are practically going to subtract the following:

$\boxed{76-100}= \ \left[\begin{array}{ccc}\bf{24\end{array}\right]$

So, from this begin understood, we would then combine both the penalties that were shotted, to the onces that weren't.

So, b subtracting these both, we would grab the result, and then smash that with the number of the penalties that were made in.

Your answer: $\boxed{\bf{76:24}}$

5 0

3 years ago