Complete the square for x and y.
7x^2 + 3y^2 - 28x - 12y = -19
7x^2 - 28x + 3y^2 - 12y = -19
7(x^2 - 4x) + 3(y^2 - 4y) = -19
7(x^2 - 4x + 4) + 3(y^2 - 4y + 4) = -19 + 28 + 12
7(x - 2)^2 + 3(y - 2)^2 = 21
Answer:
no because for right angle triangle the sum of the sq of the two smallest side is equal to the sq of biggest side
Answer:
x=5
Step-by-step explanation:
So how i came about to get this answer, was
y=15-3x
y=15-3(5)
y=15-15
y=0
I found five by testing out different numbers for x such as 1 2 3 4, but when i got to five, that was where i got the answer, as shown above.
<u>Do</u><u> </u><u>not</u><u> </u><u>forget</u><u> </u><u>about</u><u> </u>PEMDAS
3x+2(5x-3)=7
3x+10x-6=7
13x-6=7
13x=13
x=1