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3 years ago

What would you have to do to change 10 cubic feet into cubic inches?

Mathematics

2 answers:

Eduardwww [97]3 years ago

7 0

The answer to you're question is B. Multiply by 1,728

Pavlova-9 [17]3 years ago

5 0

Let's try it out

hmm, lets make up some fake dimentions

lets say we have a box that is 1ft by 2ft by 5ft
that makes 10 cubic feet

now we convert each to feet
1ft=12 inches
2ft=24 inches
5ft=12*5=60 inches

so
12*24*60=17280

alright
10 times what=17280?
divide both sides by 10
what=1728

so mulitply it by 1728 (which is 12^3)

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3 years ago

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Answer:

$\int \:3\cdot \frac{x}{\left(x-1\right)^2}dx=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C$

Step-by-step explanation:

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$\int \:\:3\cdot \frac{x}{\left(x-1\right)^2}dx$

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$\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx$

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$\mathrm{Substitute\:back}\:u=x-1$

$=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)$

$\mathrm{Add\:a\:constant\:to\:the\:solution}$

$=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C$

Therefore,

$\int \:3\cdot \frac{x}{\left(x-1\right)^2}dx=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C$

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