To solve this problem you must apply the proccedure shown below:
1. You have the following expression:
(3+3i)-(13+15i)
2. If you want to substract both terms, you need to substract the real numbers and the complex numbers. Then, you obtain:
3+3i-13-15i
(3-13)+(3i-15i)
3. Then, you obtain the following result:
-10-12i
4. Therefore, as you can see, the correct answer is the last option (option D), which is:
D. -10-12i
Answer:
i believe a is 1, b is -2, and c is 0
Step-by-step explanation:
im bad at this stuff, so i might be wrong
hope it helps
Is this the whole question?
Step-by-step explanation:
Are you done typing or there's more to it.
We are given zeros of the polynomial : 7, -11, and 2 + 8i.
Note: The radical zero always comes with the pair of plus and minus sign.
Therefore, another zero would be 2-8i.
Now, in order to find the polynomial with the zeros 7, -11, 2 + 8i and 2-8i, we need to find the factors of the polynomial.
The factors of the polynomial would be (x-7)(x+11)(x-2-8i)(x-2+8i).
Let us multiply those factors to get the standard form of the polynomial.

=

.
<h3>Therefore, correct option is 4th option

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