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fgiga [73]
3 years ago
14

Eight oranges cost $1.00. How much will 5 dozen oranges cost?

Mathematics
2 answers:
kaheart [24]3 years ago
6 0
dozen=12\ \ \ \ 5*12=60\\\\ 8\ oranges\ cost\ 1\$\\ 60\ oranges\ cost\ x\\\\ make\ proportion:\\ 8-1\\60-x\\\\cross\ multiplication\\\\ 8x=60\ \ \ | divide\ by\ 8\\\\ x=7.5\$\\\\5\ dozens\ cost\ 7.5\$\\\\
stepladder [879]3 years ago
3 0
5 dozen oranges will cost $7.50.  (Each orange costs 12.5 cents)
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34. A motorist started a journey at 10.25a.m. and ended at 6.15 p.m. Calculate the time
GenaCL600 [577]

Write the times for each hour from start time:

10:25 am

11:25 am

12:25 pm

1:25 pm

2:25 pm

3:25 pm

4:25 pm

5:25 pm

6:25 pm

There are 8 hours between 10:25 am and 6:25 pm.

they finished at 6:15 which is 10 minutes before 6:25 ( 25-15 = 10)

10 minutes less than a full hour is 50 minutes ( 60 - 10 = 50)

8 hours - 1 hour = 7 hours

7 hours + 50 minutes = 7 hours 50 minutes total time.

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3 years ago
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kogti [31]

Answer:

Step-by-step explanation:

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3 years ago
Which of the following is not an inertial reference frame? Which of the following is not an inertial reference frame?
hammer [34]
An inertial reference frame is a frame of reference in which a body remains at rest OR moves with a constant LINEAR velocity.  Answer choices A, C, and D are moving linearly at a constant rate and are all inertial frames of reference.  Answer choice E is motionless, and is therefor an inertial frame of reference. Answer choice B is rotating at a constant rate.  Rotation is not an inertial frame of reference.
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7 0
3 years ago
Element X decays radioactively with a half life of 12 minutes. If there are 160
Salsk061 [2.6K]

Answer:

It would take 75.8 minutes for the element to decay to 2 grams.

Step-by-step explanation:

The number of grams of element x, after t minutes, is given by the following equation:

X(t) = X(0)(1-r)^{t}

In which X(0) is the initial amount and r is the decay rate.

There are 160 grams of Element X

This means that X(0) = 160.

So

X(t) = X(0)(1-r)^{t}

X(t) = 160(1-r)^{t}

Half life of 12 minutes.

This means that X(12) = 0.5*X(0) = 0.5*160 = 80. So

X(t) = 160(1-r)^{t}

80 = 160(1-r)^{12}

(1 - r)^{12} = 0.5

\sqrt[12]{(1 - r)^{12}} = \sqrt[12]{0.5}

1 - r = 0.9438

So

X(t) = 160(1-r)^{t}

X(t) = 160(0.9438)^{t}

How long would it take for the element to decay to 2 grams?

This is t for which X(t) = 2. So

X(t) = 160(0.9438)^{t}

2 = 160(0.9438)^{t}

(0.9438)^{t} = \frac{2}{160}

\log{(0.9438)^{t}} = \log{\frac{2}{160}}

t\log{0.9438} = \log{\frac{2}{160}}

t = \frac{\log{\frac{2}{160}}}{\log{0.9438}}

t = 75.8

It would take 75.8 minutes for the element to decay to 2 grams.

6 0
3 years ago
If 4x - 8 = 4 , find the value of x​
Wittaler [7]

Answer:

x=3

Step-by-step explanation:

4x-8=4

4x=12

4x/4=12/4

x=3

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4 years ago
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