2/5 of 500= 200 times 0.40=£80
the rest 500-200=300
3 oranges for 50p. 100 times 0.5 =£ 50 over £130
Sam made a loss (140-130=£10)
Answer:
Area 14 = PQRS + UVW; Area 16 = ABCD + EFG
Step-by-step explanation:
PQRS: A = lw = 7 × 2 = 14
ABCD: A = lw = 4 × 4 = 16
UVW: A = ½bh = ½ × 7 × 4 = 14
EFG: A = ½bh = ½ × 8 × 4 = 16
Area 14 = PQRS + UVW
Area 16 = ABCD + EFG
Answer:
n<-27
Step-by-step explanation:
you have to get n by itself, to do this divide -3 from both sides of the equations.
-3n/-3<81/-3
n<-27
the answer is n<-27
Full Question
A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t = 0, the resulting mass—spring system is disturbed from its rest state by the force F (t) = 20 cos(8t). The force F (t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds.
Determine the spring constant k.
Answer:
Spring Constant = 1000Nm^-1
Step-by-step explanation:
Given
Mass = 10kg
Spring Extension = 9.8cm
Spring Constant K = Force/Extension
Force = Mass * Acceleration
Force = 10 * 9.8 = 9.8N
Spring Extension = 9.8 cm = 9.8 /100 = 0.098 m
Spring constant = 98 / 0.098
Spring Constant = 1000Nm^-1
Answer: 105 miles
Step-by-step explanation:
You can write an equation for this problem and solve it.
32 miles=1/3x-3, where x is equal to the total length of the highway.
35=1/3x, and then you multiply by 3, to get x=105