Answer:
{58.02007 , 61.97993]
Step-by-step explanation:
Data are given in the question
Sample of cars = n = 121
Average speed = sample mean = 60
Standard deviation = sd = 11
And we assume
95% confidence t-score = 1.97993
Therefore
Confidence interval is
![= [60 - \frac{1.97993 \times 11}{\sqrt{121} }] , [60 + \frac{1.97993 \times 11}{\sqrt{121} }]](https://tex.z-dn.net/?f=%3D%20%5B60%20-%20%20%5Cfrac%7B1.97993%20%5Ctimes%2011%7D%7B%5Csqrt%7B121%7D%20%7D%5D%20%2C%20%20%5B60%20%2B%20%20%5Cfrac%7B1.97993%20%5Ctimes%2011%7D%7B%5Csqrt%7B121%7D%20%7D%5D)
= {58.02007 , 61.97993]
Basically we applied the above formula to determine the confidence interval
The derivative of the function csc (5x) can be determined by following the trigonometric rule of differentiation. In this case, the derivative of csc x is -csc x cot x while that of 5x is 5. The total derivative and the answer to the problem asking for the is <span>derivative of csc(5x) is </span>-5 csc<span> 5x cot 5x. </span>