Answer:
19/20
Step-by-step explanation:
7/10+1/4
=14/20+5/20
=19/20
Answer:
i think your question is missing something??
Step-by-step explanation:
3(4) + 6 = 7 (2(4)-3)
12 + 6 = 7 (8-3)
18 = 7 (5)
18 = 35?
Answer:
Lowest is 100
Highest is 125
Step-by-step explanation:
We use the 5 number summary to be the foundation of a graphical representation referred to as the box plot. One box would move from one quartile which is the lowest quartile Q1 to the another quartile Q3 which is the upper quartile.
Now if a box plot is to be made given the the information in this question, the box is going to go from Quartile 1 to Quartile 3.
Then the Lowest value would be 100 and the highest 125
Answer:
y=-2/5x-3
Step-by-step explanation:
the slope is m and the y intercept is b
If I read the question correctly, the information about the 80x80 fencing and the grass region are all irrelevant information.
In order to find the area of the side walk we are going to use the formula A=pi(r^2) where r = the radius. The diameter of the pool is 60 feet and the the sidewalk is 5 feet bigger all around meaning we had 5 feet to both sides of this 60 feet giving you an overall diameter of 70 feet (or 60 + 5*2). To find the radius take half of the diameter. 70/2 = 35.
Now we plug in 35 to the equation. A = Pi(35^2) = 1225pi. Leave your answer like this as we are not finished and will need to round at the end for an accurate answer. This is NOT the end, that number is the area of the sidewalk AND the pool.
The sidewalk is not a full circle, just a border so we now have to find the area of the actual pool and subtract it from this 1225pi for the sidewalk's area. Same formula, Area = pi(r^2). The diameter of the pool is 60 meaning the radius is 30 (or 60/2). Plug into the equation, pi(30^2) = 900pi.
Now do 1225pi - 900pi to get 325pi. Break out your calculator and hit the approximation button. 325pi is approximately 1021.018 if rounded to 3 decimal places.
The area of the 5-foot wide sidewalk encircling the pool is approximately 1021.018 square feet.
