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spayn [35]
3 years ago
5

Write a real -world word problem that can be solved using elapsed time. Include the solution.

Mathematics
1 answer:
Olegator [25]3 years ago
8 0
Greg walks into a store at 6:30 a.m.
The store opens at 8:00 a.m.
How much time does Greg have until the store opens?
8:00-6:30=. 1 hour and 30 minutes
You might be interested in
What is the product? 3x^5(2x^2+4+1)
const2013 [10]

Answer:

6x^{7} +15x^{5}

Step-by-step explanation:

3x^{5}(2x^{2} +4+1)

Multiply 3x^{5} by each term in the parentheses.

6x^{7} + 12x^{5} +3x^{5}

Now, all you have to do is simplify.

6x^{7} +15x^{5}

5 0
3 years ago
In one town 44% of all voters are Democrats if two voters are randomly selected for a survey find the probability that they are
kenny6666 [7]

Answer:

0.194


Step-by-step explanation:

Probability that BOTH are democrats means probability of <u>"one being democrat"</u> AND <u>"another also being democrat"</u>.

The AND means we need to MULTIPLY the individual probability of a person being democrat.

Probability that a voter is democrat is 44% (0.44) -- stated in the problem


Now, Probability BOTH being Democrats is simply MULTIPLYING 0.44 with 0.44

0.44*0.44=0.1936

Rounded to nearest thousandth, 0.194

Last answer choice is correct.

6 0
3 years ago
A geometry student wants to draw a rectangle inscribed in the ellipse
IceJOKER [234]
What is the question?
6 0
3 years ago
Darnell wrote this expression to describe the number of bus rides he has left on his bus pass. p – 12 Which situation could be d
Orlov [11]
I think the answer is B. Darnell does not know how many rides he has already used. He knows he has 12 bus rides left on the bus pass.
.
3 0
3 years ago
What is the vertex form of Y = x2 - 6x + 6?
ahrayia [7]

Answer:

\large\boxed{y=(x-3)^2-3}

Step-by-step explanation:

The vertex form of a quadratic equation <em>y = ax² + bx + c:</em>

<em>y = a(x - h)² + k</em>

(h, k) - coordinates of a vertex

We have the equation <em>y = x² - 6x + 6</em>.

Convert to the vertex form:

y=x^2-2(x)(3)+6\\\\y=\underbrace{x^2-2(x)(3)+3^2}_{(*)}-3^2+6\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2\qquad(*)\\\\y=(x-3)^2-9+6\\\\y=(x-3)^2-3\to h=3,\ k=-3

7 0
3 years ago
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