The width of the pathway is 3m
Step-by-step explanation:
Let the width of the pathway be 'w'
The area will be 130 square meters
The dimensions of the garden is 10 x 7
Area = (10+w) (7+w)
130 = 70 + 17w + w^2
w^2 + 17w - 60 = 0
w^2 +20w - 3w - 60 = 0
w ( w + 20) - 3 ( w + 20) = 0
(w + 20) (w - 3) = 0
w = -20 ( or) w = 3
w is the width and cannot be negative.
So, w = 3 meters
The width of the pathway is 3m
Answer:
y= 2-2x
Step-by-step explanation:
Isolate y.
Not sure if I'm right but I think it's 3(x - 6) (x^2 + 5x)
Step-by-step explanation:
3x^3 - 3x^2 - 90x
Apply GCF: 3 (x^3 - x^2 - 30)
Split 30 into -6 and 5
(x^3 - 6x^2) (5x^2 - 30x)
GCF of both: x^2 (x - 6) and 5x (x - 6)
DON'T FORGET TO CARRY THE 3
And your answer is 3 (x - 6) (x^2 + 5x)
Answer:
x = 7
Step-by-step explanation:
Similar figures have sides that are proportional. Setting up a proportion for the sides of the figures will help solve for 'x':
Cross-multiply: 3(x + 1) = 6(x - 3)
Distribute: 3x + 3 = 6x - 18
Combine like terms: 21 = 3x
Solve for 'x': x = 7
