let's recall that in an isosceles triangle, the twin sides make twin angles at the bottom/base, so on the triangle on the left-side, if the "vertex" atop has an angle of 116°, then the twin sides below are simply 180° - 116 = 64, split that in half and that's 32° each.
The same is true for the isosceles triangle on the right side. Also recall that a flat-line is always 180°, 32 + 72 + 76 = 180.
Check the picture below.
Answer:
Refer below explanation.
Step-by-step explanation:
Given : two triangles ∆QPK and ∆LMK.
We have to show ∆QPK ≅ ∆LMK.
Two triangles are similar if ratio of the corresponding sides are equal and measure of corresponding angles are equal.
Statement 1)
QK=16, PK=26, MK=65, KL=40 ( Reason: Given)
Statement 2 )
(reason : ratio of corresponding sides)
Statement 3)
Thus,
(reason: simplify ratios)
Statement 4)
∠MKL = ∠PQK (reason : Vertically opposite angles)
Statement 5)
∆QPK ≅ ∆LMK (reason : Side-angle-side)
Side angle side similarity criterion states that two angles are similar if the ratio of their corresponding sides and angle between these sides are equal then triangles are similar.
