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3 years ago

6

0.04 × 0.61 =Tell me how to work this out

2 answers:

Sphinxa [80]3 years ago

6 0

0.0244 is the answer

brilliants [131]3 years ago

3 0

--0.04->6 X 4 =24
X0.61---|^|------|--|
--------<-=-------|--|
--0.04-----------|--|
+2.40------------|--|
--------<-=-------|--|
2.44<---------------|
your answer is 2.44/ 0.04 X 0.61 = 2.44

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2 years ago

What is the x-intercept for 12x+2=17y

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3 years ago

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2 years ago

Read 2 more answers

write an equation in slope intercept form for the line that passes through (4, -4) and is parallel to 3x+4x=2y-9

photoshop1234 [79]

Answer:

$\large\boxed{y=\dfrac{7}{2}x-18}$

Step-by-step explanation:

The slope-intercept form of an equation of a line:

$y=mx+b$

Convert the equation of a line 3x + 4x = 2y - 9 to the slope-intercept form:

$3x+4x=2y-9$

$7x=2y-9$ <em>add 9 to both sides</em>

$7x+9=2y$ <em>divide both sides by 2</em>

$\dfrac{7}{2}x+\dfrac{9}{2}=y\to y=\dfrac{7}{2}x+\dfrac{9}{2}$

Parallel lines have the same slope. Therefore we have the equation:

$y=\dfrac{7}{2}x+b$

Put the coordinates of the point (4, -4) to the equation:

$-4=\dfrac{7}{2}(4)+b$

$-4=7(2)+b$

$-4=14+b$ <em>subtract 14 from both sides</em>

$-18=b\to b=-18$

Finally we have the equation:

$y=\dfrac{7}{2}x-18$

8 0

3 years ago

maksim [4K]

<u>Part A</u>

<u /> $4x^2 -7x-15=0\\\\(4x+5)(x-3)=0\\\\x=-\frac{5}{4}, 3$

So, the x-intercepts are $\boxed{\left(-\frac{5}{4}, 0 \right), (3,0)}$

<u>Part B</u>

The vertex will be a minimum because the coefficient of $x^2$ is positive.

The x-coordinate of the vertex is $x=-\frac{-7}{2(4)}=\frac{7}{8}$

Substituting this back into the function, we get $f\left(\frac{7}{8} \right)=4\left(\frac{7}{8} \right)^2 -7\left(\frac{7}{8} \right)^2 -15=-\frac{289}{16}$

So, the coordinates of the vertex are $\boxed{\left(\frac{7}{8}, -\frac{289}{16} \right)}$

<u>Part C</u>

Plot the vertex and the x-intercepts and draw a parabola that passes through these three points.

The graph is shown in the attached image.

7 0

1 year ago