All categories

3 years ago

Ratios

Mathematics

1 answer:

a_sh-v [17]3 years ago

4 0

Answer: hey hey hey shy shy

Step-by-step explanation:

mzksajd sjkaldjl slkasjdlaf

You might be interested in

A hot air balloon is 910 feet above sea level. It is rising at a rate of 4 feet fee second. How high is the hot air balloon afte

nalin [4]

Answer:

1230

Step-by-step explanation:

80 x 4 = 320

320 + 910 = 1230

5 0

1 year ago

Given a function I and a subset A of its domain, let I(A) represent the range of lover the set A; that is, I(A) = {I(x) : x E A}

Ede4ka [16]

Step-by-step explanation:

(a)

Using the definition given from the problem

$f(A) = \{x^2 \, : \, x \in [0,2]\} = [0,4]\\f(B) = \{x^2 \, : \, x \in [1,4]\} = [1,16]\\f(A) \cap f(B) = [1,4] = f(A \cap B)\\$

Therefore it is true for intersection. Now for union, we have that

$A \cup B = [0,4]\\f(A\cup B ) = [0,16]\\f(A) = [0,4]\\f(B)= [1,16]\\f(A) \cup f(B) = [0,16]$

Therefore, for this case, it would be true that $f(A\cup B) = f(A)\cup f(B)$ .

(b)

1 is not a set.

(c)

To begin with

$A\cap B \subset A,B$

Therefore

$g(A\cap B) \subset g(A) \cap g(B)$

Now, given an element of $g(A) \cap g(B)$ it will belong to both sets, therefore it also belongs to $g(A\cap B)$ , and you would have that

$g(A)\cap g(B) \subset g(A \cap B)$ , therefore $g(A)\cap g(B) = g(A \cap B)$ .

(d)

To begin with $A,B \subset A \cup B$ , therefore

$g(A) \cup g(b) \subset g(A\cup B)$

7 0

3 years ago

-3(-x+4)=5+3(x+1) please help

Lostsunrise [7]

Answer:

No solution.

Step-by-step explanation:

Step 1: Write equation

-3(-x + 4) = 5 + 3(x + 1)

Step 2: Solve for x

Distribute: 3x - 12 = 5 + 3x + 3
Combine like terms: 3x - 12 = 3x + 8
Subtract 3x on both sides: -12 ≠ 8

Here, we see that x has to equal no solution. No value of x would make the equation true.

3 0

3 years ago

Read 2 more answers

What is the shaded portion of the circle

blagie [28]

Answer:

$(5\pi-11.6)\ ft^{2}$

Step-by-step explanation:

we know that

The area of the shaded region is equal to the area of the sector minus the area of the triangle

step 1

Find the area of the circle

the area of the circle is equal to

$A=\pi r^{2}$

we have

$r=5\ ft$

substitute

$A=\pi (5)^{2}$

$A=25\pi\ ft^{2}$

step 2

Find the area of the sector

we know that

The area of the circle subtends a central angle of 360 degrees

by proportion find out the area of a sector by a central angle of 72 degrees

$\frac{25\pi}{360}=\frac{x}{72}\\ \\x=72*25\pi /360\\ \\x=5\pi\ ft^{2}$

step 3

Find the area of triangle

The area of the triangle is equal to

$A=\frac{1}{2}(2.9+2.9)(4)= 11.6\ ft^{2}$

step 4

Find the area of the shaded region

Subtract the area of the triangle from the area of the sector

$(5\pi-11.6)\ ft^{2}$

8 0

2 years ago

Solve the equation, and check the solutions (√x+3)+6=3.

larisa86 [58]

Answer:

The equation has no solution.

Step-by-step explanation:

Hi there!

First, let´s write the equation:

(√x + 3) + 6 = 3

To solve the equation, let´s subtract 6 to both sides of the equation:

√x + 3 = -3

subtract 3 to both sides of the equation:

√x = -6 (the square root of any number can´t be negative, but let´s solve it anyway and then check the solution).

Square both sides of the equation:

x = 36

Now, let´s check the solution:

(√x + 3) + 6 = 3

x = 36

(√36 + 3) + 6 = 3

(6 + 3) + 6 = 3

9 + 6 = 3

15 ≠ 3

Then, the equation has no solution.

Have a nice day!

6 0

2 years ago