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posledela
2 years ago
8

PLEASE HELP ME!!! ASAP!! ITS ALMOST DUE!!

Mathematics
1 answer:
Natali [406]2 years ago
4 0

Answer:

it would be the 3 answer

Step-by-step explanation:

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The answer is 15! Because 5x3 is 15
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3 years ago
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Find a number smaller than 19 that has more factors than the numbers 19 21 23 25
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18 has more factors than all of those numbers.

1, 2, 3, 6, 9, 18 are all the factors of 18.

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2 years ago
In a (blank) , one ratio compares a part to a whole
cluponka [151]
I think it is a rate?           

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3 years ago
How many and what type of solutions does the equation have?
Natali [406]
Let's solve the equation 2k^2 = 9 + 3k
First, subtract each side by (9+3k) to get 0 on the right side of the equation
2k^2 = 9 + 3k
2k^2 - (9+3k) = 9+3k - (9+3k)
2k^2 - 9 - 3k = 9 + 3k - 9 - 3k
2k^2 - 3k - 9 = 0

As you see, we got a quadratic equation of general form ax^2 + bx + c, in which a = 2, b= -3, and c = -9.
Δ = b^2 - 4ac
Δ = (-3)^2 - 4 (2)(-9)
Δ<u /> = 9 + 72
Δ<u /> = 81

Δ<u />>0 so the equation got 2 real solutions:
k = (-b + √Δ)/2a = (-(-3) + √<u />81) / 2*2 = (3+9)/4 = 12/4 = 3
AND
k = (-b -√Δ)/2a = (-(-3) - √<u />81)/2*2 = (3-9)/4 = -6/4 = -3/2

So the solutions to 2k^2 = 9+3k are k=3 and k=-3/2

A rational number is either an integer number, or a decimal number that got a definitive number of digits after the decimal point.

3 is an integer number, so it's rational.
-3/2 = -1.5, and -1.5 got a definitive number of digit after the decimal point, so it's rational.

So 2k^2 = 9 + 3k have two rational solutions (Option B).

Hope this Helps! :)
7 0
3 years ago
Read 2 more answers
Help ASAP pls giving brainliest
inna [77]
After arranging the data from least to greatest:

Q1: 12.5
Q3: 16
IQR ( Q3-Q1) : 3.5
6 0
3 years ago
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