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photoshop1234 [79]
3 years ago
8

Which of the following types of access controls do not describe a lock? (a)- Directive (b)- Physical (c)- Preventative (d)- Dete

rrent
Computers and Technology
1 answer:
Mrac [35]3 years ago
7 0

Answer:

Directive

Explanation:

A directive access control is used to direct, confine, or control the actions of subject to force compliance with security policies. Some examples of direct access controls are: security guards, guard dogs, posted notifications, monitoring, supervising, work task procedures, and awareness training. It can also be categorized by how it is implemented; for example, it can be administrative, logical/technical, or physical.

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Which are benefits of modeling a solution? Choose all that apply. allows you to be sure the problem and solution are understood
labwork [276]

Answer:

A,B,D

A. Allows you to be sure the problem and solution are understood

B. Presents the solution in a manner that is easy to share

C. Is a starting point for all other activities

4 0
4 years ago
Read 2 more answers
Two machines can finish a job in StartFraction 20 Over 9 EndFraction hours. Working​ alone, one machine would take one hour long
Alborosie

<em><u>Answer</u></em>

5 hours

<em><u>Explanation</u></em>

The two working together can finish a job in

\frac{20}{9}  \: hours

Also, working alone, one machine would take one hour longer than the other to complete the same job.

Let the slower machine working alone take x hours. Then the faster machine takes x-1 hours to complete the same task working alone.

Their combined rate in terms of x is

\frac{1}{x}    +  \frac{1}{x - 1}

This should be equal to 20/9 hours.

\frac{1}{x}  +  \frac{1}{x - 1}  =  \frac{9}{20}

Multiply through by;

20x(x - 1) \times \frac{1}{x}  +20x(x - 1) \times   \frac{1}{x - 1}  =  20x(x - 1) \times \frac{9}{0}

20(x - 1)  +20x = 9x(x - 1)

20x - 20+20x = 9{x}^{2}  - 9x

9{x}^{2}  - 9x - 20x - 20x + 20= 0

9{x}^{2}  - 49x  + 20= 0

Factor to get:

(9x - 4)(x - 5) = 0

x =  \frac{4}{9}  \: or \: x = 5

It is not feasible for the slower machine to complete the work alone in 4/9 hours if the two will finish in 20/9 hours.

Therefore the slower finish in 5 hours.

8 0
3 years ago
What is a flowchart and write it's work​
Artist 52 [7]

Answer: A flowchart is a type of diagram that represents an algorithm, workflow or process. The flowchart shows the steps as boxes of various kinds, and their order by connecting the boxes with arrows. ... Flowcharts are used in analyzing, designing, documenting or managing a process or program in various fields.

Explanation: brainliest plz!

3 0
3 years ago
Why do we need multitasking functionality in an Operating System?
Leokris [45]

Answer:

Multitasking is a process in which we do multiple task at a time.    

In computing system, multitasking is the concept of performing different types of multiple task and process over a certain period of time by executing simultaneously.

Operating system basically allow various task to run simultaneously by the user. In an operating system, each task consume storage system and all the other resources.

Multitasking function facilitate memory isolation in the processor and also supported different levels of security system in the operating system. For example, "a programmer working on any program in a system and as well as listening the music then, it perform multiple task at the same time".

7 0
3 years ago
Write an algorithm that prints out all the subsets of 3 elements of a set of n elements. The elements of the set are stored in a
Ksenya-84 [330]

void Print_3_Element_Subsets(int n,const element_type S[])

{

if(n<3) // condition to check if list have less than 3 elements

{

print("No subset found");

}

for(int i =0; i < n ; i++)

{

for(int j =i+1; j < n ; j++)

{

for(int k =j+1; k < n ; k++)

{

print(S[i],S[j],S[k]);

}

}

}

}

C++ Implementation;

#include<cstdlib>

#include<time.h>

using namespace std;

int S1[5]= {1,2,3,4,5};

int n1 = 5;

int S2[2]={1,2};

int n2 = 2;

void Print_3_Element_Subsets(int n,const int S[])

{

if(n<3) // condition to check if list have less than 3 elements

{

printf("No subset found\n");

}

printf("3 Subsets are\n");

for(int i =0; i < n ; i++)

{

for(int j =i+1; j < n ; j++)

{

for(int k =j+1; k < n ; k++)

{

cout<<S[i]<<" "<<S[j]<<" "<<S[k]<<endl;

}

}

}

}

int main()

{

cout<<"Case 1"<<endl;

Print_3_Element_Subsets(n1,S1);

cout<<endl<<"Case 2"<<endl;

Print_3_Element_Subsets(n2,S2);

}

OUTPUT

Case 1

3 Subsets are

1 2 3

1 2 4

1 2 5

1 3 4

1 3 5

1 4 5

2 3 4

2 3 5

2 4 5

3 4 5

Case 2

No subset found

3 Subsets are

--------------------------------

Process exited after 0.0137 seconds with return value 0

Press any key to continue . . .

7 0
3 years ago
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