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rosijanka [135]
4 years ago
9

The prepaid tuition plan covers

Computers and Technology
2 answers:
rusak2 [61]4 years ago
8 0
Hey there!

A prepaid tuition plan is a plan that allows you to pay the current rate of tuition now (say, years in advance), even if it's much higher than the time when the payment for tuition would actually be paid. This plan is great for anyone who wants to pay a lower price for high–cost education now (even if their kid isn't college age yet) and not have to worry about economic standing or inflation in the future that could drive the tuition prices up. 

The plan only covers tuition and other similar fees. You can not purchase books or room and board with it in advance. So, your answer should be: C. Tuition and Fees. 

Hope this helped you out! :-)
Tema [17]4 years ago
5 0

tution and fees it covers

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In cryptocurrency, a block is only considered valid if it has a.
melomori [17]

Answer: Token

Explanation: The token gives proof that it is yours.

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3 years ago
A SQL data source is a control that can be used to get data from a SQL ________________ file such as a Microsoft SQL Server file
AleksAgata [21]

Answer:

The answer is "Data"

Explanation:

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3 years ago
Adam has to write a paper where the margins need to be set to these measurements: Left: 1.5" Right: 4" Bottom: 1" Top: 1"
Sholpan [36]

In Microsoft Word, he should go to Page Layout and then to Margins.

8 0
4 years ago
Consider the following method, sumRows, which is intended to traverse all the rows in the two-dimensional (2D) integer array num
Lena [83]

Answer:

Option C: {{4, 1, 7}, {-10, -11, -12}}

Explanation:

There is a logical error in the inner loop.

for (int j = 0; j < num.length; j++)

It shouldn't be "j < num.length" as the iteration of the inner loop will be based on the length of the row number of the two dimensional array. The inner loop is expected to traverse through the every column of the same row in the two dimensional array and sum up the number. To fix this error, we can change it to

for (int j = 0; j < r.length; j++)

8 0
3 years ago
Take the program written last weekend that creates a deck of cards, shuffles them, and then lists them out. Modify the program t
Mars2501 [29]

Answer: Here, you might need to make some changes to format it how you'd like, but it gives you the desired output :)

Explanation:

import random as chunky

def play():

   hand1, hand2 = [], []

   for n in range(5):

       hand1.append(chunky.choice(cardList))

       hand2.append(chunky.choice(cardList))

   print("Hand 1: ", end= "")

   for n in hand1:

       print(n, end= " ")

   print()

   print("\nHand 2: ", end= "")

   for n in hand2:

       print(n, end= " ")

   print()

   while "A" in hand1:

       hand1[hand1.index("A")] = 11

   while "A" in hand2:

       hand2[hand2.index("A")] = 11

   print(f"\nHand 1 Total: {sum(hand1)}  Hand 2 Total: {sum(hand2)}")

   print("\nHand 1 WINS!") if sum(hand1) > sum(hand2) else print("\nHand 2 WINS!")

cardList = [1,2,3,4,5,6,7,8,9,10,"A"] #Skipped King, Queen, and Jack. Did not know how to incorperate them

chunky.shuffle(cardList)

looper = True

while looper == True:

   play()

   x = input("\n\nWould you like to go again?(y/n): ")

   if x.lower() == "n":

       quit()

8 0
4 years ago
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