Every program that interacts with people responds to a specific set of commands. The set of commands and the syntax for entering them is called the user interface and varies from one program to another. The DOS operating system makes a distinction between internal and external commands.
Answer:
Here is the script:
function dd = functionDMS(dd)
prompt= 'Enter angle in DD form ';
dd = input(prompt)
while (~checknum(dd))
if ~checknum(dd)
error('Enter valid input ');
end
dd = input(prompt)
end
degrees = int(dd)
minutes = int(dd - degrees)
seconds = ( dd - degrees - minutes / 60 ) * 3600
print degrees
print minutes
print seconds
print dd
Explanation:
The script prompts the user to enter an angle in decimal degree (DD) form. Next it stores that input in dd. The while loop condition checks that input is in valid form. If the input is not valid then it displays the message: Enter valid input. If the input is valid then the program converts the input dd into degrees, minutes and seconds form. In order to compute degrees the whole number part of input value dd is used. In order to compute the minutes, the value of degrees is subtracted from value of dd. The other way is to multiply remaining decimal by 60 and then use whole number part of the answer as minutes. In order to compute seconds subtract dd , degrees and minutes values and divide the answer by 60 and multiply the entire result with 3600. At the end the values of degrees minutes and seconds are printed. In MATLAB there is also a function used to convert decimal degrees to degrees minutes and seconds representation. This function is degrees2dms.
Another method to convert dd into dms is:
data = "Enter value of dd"
dd = input(data)
degrees = fix(dd);
minutes = dd - degrees;
seconds = (dd-degrees-minutes/60) *3600;
Answer:
The answer to this question is given below in the explanation section.
Explanation:
This program is written in C++.
#include <iostream>
using namespace std;
int main()
{
string word;// variable for taking user input
int cond;// to set condition true if user preses the stop and exit from loop
cout<<"Enter word: \n";
cin>>word;
do// start while loop
{
if(word=="stop" || word =="STOP" || word == "Stop")// if user enter word stop, then program exit
{
cond=0;
}
else//otherwise loop continue
{
cout<<" You Entered "+ word +"\n";
cout<<"Enter word: \n";
cin>>word;
cond=1;
}
}
while(cond == 1);// if user don't enter word "stop" loop run continuesly.
cout<<"Program exit";
return 0;
}
