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sergey [27]
3 years ago
7

Write an inequality that represents the following problem.

Mathematics
1 answer:
Arlecino [84]3 years ago
5 0
35 + 0.05m > 50 + 0.01m
0.05m > 15 + 0.01m
0.04m > 15
m > 15 x 25
m > 375

You must send more than 375 messages.
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What is the value of n in the equation ? n = 0 n = 2 n = 4 n = 6
RideAnS [48]

Answer:

N=2

Step-by-step explanation:

N=2

5 0
3 years ago
Read 2 more answers
PLEASE HELP WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!
Paraphin [41]

the overhead, fixed costs, is $1000.

the variable cost is $200, so if she sells "x" tiles, then her costs is 200*x or 200x.

total costs then will just be C(x) = 200x + 1000.

namely both costs added together.

Revenue is just how much it's been taken in from the sales, since each tile is selling for $240, then the revenue is simply 240*x or just R(x) = 240x.

break even point is when those two guys equal each other

\bf \stackrel{R(x)}{240x}=\stackrel{C(x)}{200x+1000}\implies 40x=1000\implies x=\cfrac{1000}{40}\implies x=25

what if the cost for each tile were $220, 20 bucks more?

\bf \stackrel{R(x)}{240x}=\stackrel{C(x)}{220x+1000}\implies 20x=1000\implies x=\cfrac{1000}{20}\implies x=50

well, if the cost for each tile is $200, her break-even point is at 25 units, namely once she has sold 25 tiles, she's has lost nothing, has won nothing either, but hasn't lost anything.

if the cost is however $220 instead, her break-even point comes much later, at 50 units, so she'll have to sell more tiles in order to not have any losses, so she's worse off if the cost is more or course.

4 0
3 years ago
Pls help me if your good at math
OLEGan [10]

Answer:

First bank last function

Second blank, the middle function

Third blank, middle function

Fourth blank, first function

7 0
2 years ago
Last week, a candle store received $355.60 for selling 20 candles. Small candles sell for $10.98 & large candles sell for $2
muminat
The answer is B. They sold 8
7 0
2 years ago
Can someone please teach me how to do this? You can please do like 2 questions and please explain exactly how you got the answer
spayn [35]

All of these questions require one thing: trigonometric functions.

There are 3 main trigonometric functions, which can only be used on right triangles: sine, cosine, and tangent.

Sine = opposite / hypotenuse

Cosine = adjacent / hypotenuse

Tangent = opposite / adjacent

When trying to figure out what function to use, we always start by looking from the angle. Take problem a, for example. Looking from angle E, of which the value is not given, we have the side opposite and the side adjacent. Therefore, we should use the tangent function.

---The hypotenuse is always the longest side of the triangle. It is never considered the opposite or adjacent side.

Let's set up our function with the given information from problem a.

tan(x) = 9.7 / 5.2

---The tangent of an unknown angle is equal to the quotient of the opposite side and the adjacent side.

Now, solving for the value of x will require a calculator. We'll need to use what's called an inverse trigonometric function. Most calculators have these directly above the regular trigonometric functions, and the inverse functions are accessed using a "second" key.

---Ensure that your calculator is in degrees, not radians!

x = tan^-1(9.7 / 5.2)

x = 61.805 = 62 degrees

Next, let's take a look at problem b. This time, we're solving for a side length instead of an angle. But, we're still going to start by looking from our angle.


Looking from the 38 degree angle, we are given the adjacent side and an unknown hypotenuse. Therefore, we should use the cosine function.

cosine(38) = 53.1 / r

---The cosine of a 38 degree angle is equal to the quotient of 53.1 and an unknown hypotenuse, r.

Use your algebra skills to isolate the variable r.

r * cosine(38) = 53.1

r = 53.1 / cosine(38)

---From here, all you need to do is plug this into your calculator. Since we are solving for a side length (and given an angle), we are just using the regular trigonometric function buttons on the calculator.

r = 67.385 = 67.4 units

Hope this helps!

4 0
2 years ago
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