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jeka57 [31]
3 years ago
5

DVDS are on sale for $24 each Felipe writes expression 4*24 to find the cost in dollars of

Mathematics
2 answers:
kirill115 [55]3 years ago
8 0
4(18+6) = 4*18 + 4*6 = 72 +  24 = 96
klemol [59]3 years ago
5 0

we know that

<u>The distributive property</u> tells us how to solve expressions in the form of

a(b + c)=ab+ac

then

we need to remember to multiply first, before doing the addition

in this problem

Let

a=4

(b+c)=24

(b+c)=20+4

substitute

4*24=4*(20+4)\\=4*20+4*4\\=80+16\\=\$96

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What is the area of a rectangle whose length is 3x and breadth is 2x
kherson [118]

Answer:

Your answer is <em>6x</em>

Step-by-step explanation:

Given,

          length(l)     = 3x

          breadth(b) = 2x

          area of a rectangle(A) = ?

Now,

A = l*b

A = 3x*2x

A = 6x    ans.

Hope its helpful!

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2 years ago
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What is the cube root of 57 R cubed
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Approximately 3.849 is the cube root of 57 cube root.
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3 years ago
Select the option that best describes the relationship
WINSTONCH [101]

Answer:

4th one its negative,linear association

Step-by-step explanation:

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2 years ago
Each patron pays an annual fee of $36 to the library. If the library collects $20,304 from the annual fee, how many patrons are
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Answer:

564 patrons.

Step-by-step explanation:

20,304/36 = 564

5 0
2 years ago
How many terms are there in the sequence 1, 8, 28, 56, ..., 1 ?
BabaBlast [244]

Answer:

9 terms

Step-by-step explanation:

Given:  

1, 8, 28, 56, ..., 1

Required

Determine the number of sequence

To determine the number of sequence, we need to understand how the sequence are generated

The sequence are generated using

\left[\begin{array}{c}n&&r\end{array}\right] = \frac{n!}{(n-r)!r!}

Where n = 8 and r = 0,1....8

When r = 0

\left[\begin{array}{c}8&&0\end{array}\right] = \frac{8!}{(8-0)!0!} = \frac{8!}{8!0!} = 1

When r = 1

\left[\begin{array}{c}8&&1\end{array}\right] = \frac{8!}{(8-1)!1!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8

When r = 2

\left[\begin{array}{c}8&&2\end{array}\right] = \frac{8!}{(8-2)!2!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} =2 8

When r = 3

\left[\begin{array}{c}8&&3\end{array}\right] = \frac{8!}{(8-3)!3!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56

When r = 4

\left[\begin{array}{c}8&&4\end{array}\right] = \frac{8!}{(8-4)!4!} = \frac{8!}{4!3!} = \frac{8 * 7 * 6 * 5 * 4!}{4! *4*3* 2 *1} = \frac{8 * 7 * 6*5}{4*3 *2 *1} = 70

When r = 5

\left[\begin{array}{c}8&&5\end{array}\right] = \frac{8!}{(8-5)!5!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56

When r = 6

\left[\begin{array}{c}8&&6\end{array}\right] = \frac{8!}{(8-6)!6!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} = 28

When r = 7

\left[\begin{array}{c}8&&7\end{array}\right] = \frac{8!}{(8-7)!7!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8

When r = 8

\left[\begin{array}{c}8&&8\end{array}\right] = \frac{8!}{(8-8)!8!} = \frac{8!}{8!0!} = 1

The full sequence is: 1,8,28,56,70,56,28,8,1

And the number of terms is 9

3 0
3 years ago
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