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3 years ago

What is the value of the function when x = 4? y = 3x + 7

2 answers:

8 0

2x - 3y = 7 and -3x + y = 7..multiply Equation 2 by THREE and add to Equation 1
-9x + 3y = 21...........................watch the y's disappear
-7x........ = 28
x = -4
substitute -4 instead of x in either of the ORIGINAL equations

2x - 3y = 7
2(-4) - 3y = 7
-8 -3y = 7..........add 8 to both sides
-3y = 15
y = -5

im not sure

denpristay [2]3 years ago

8 0

$y=3x+7\ \ \ | substitute\ x=4\\\\
y=3*4+7\\\\
y=12+7=19\\\\
Value\ of\ function\ is\ 19.$

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Use a positive or negative number to represent a stock market loss of $1,500.

Natasha_Volkova [10]

Answer:

negative

Step-by-step explanation:

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2 years ago

Find the difference in simplest form for 3/5-1/7

morpeh [17]

Answer: 0.457

multiply 3 by 7, and get 21

multiply 1 by 5, and get 5.

5 × 7 = 35.

fraction: 21/35 and 5/35

Subtract the numerators

21 − 5 = 16 = 16/35

Now we need to simplify the fraction that we have.

17 is larger than 16. So we're done reducing numbers.

Our final answer: $16/35$

Hope this helps!

I am joyous to assist anytime.

~Jarvis

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3 years ago

Points P and Q belong to segment AB . If AB = a, AP = 2PQ = 2QB, find the distance: between the midpoints of segments AP and QB

amid [387]

Answer:

$\frac{a}{8}$

Step-by-step explanation:

AB = a

AP = 2PQ = 2QB

AB = AP + PQ + QB

= AP + $\frac{AP}{2}$ + $\frac{AP}{2}$

AB = 2AP

AP = $\frac{a}{2}$ -----(1)

And we know QB = $\frac{AP}{2}$

QB= AP/2 = $\frac{a}{4}$ ---------(2)

Now midpoint of AP = $\frac{a}{2}$ × $\frac{1}{2}$ = $\frac{a}{4}$

and midpoint of QB = $\frac{a}{4}$ × $\frac{1}{2}$ = $\frac{a}{8}$

distance between these midpoints = $\frac{a}{4}$ - $\frac{a}{8}$

= $\frac{a}{8}$

4 0

3 years ago

Read 2 more answers

15 points! Thanks so much!!

Georgia [21]

For this question it is the difference of two perfect squares. This means your final answer will be (2x - 5)(2x + 5). This answer is not listed so it would be none of the above.

After review, B technically works because it is the difference of two perfect squares. This allows you to take the square root of each term while ignoring the sign and then place that back in with the original sign.

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2 years ago

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Answer:

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Step-by-step explanation:

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2 years ago