I haven’t done this type of math in a long time so I am not 100% sure but I do remember that all you have to do is count how much heads there is in the first row and how much tails there were in the first row and you keep doing this for all of the rows. Hope that helped:))
Taber invested money in an account where interest is compounded every year. He made no withdrawals or deposits.
The function A(t) = 525(1 + 0.05)t represents the amount of money in the account after t years.
The function is explained as below
Amount = Principal * ( 1 + interest rate ) ^ time
Principal is the amount that is invested in the beginning
Therefore, Taber originally invested $525
Answer:
log4(1024)=5
Step-by-step explanation:
the 4 is a subscript
Answer:
x=2
Step-by-step explanation:
divide -5 to both sides to isolate the x. two negatives make a positive therefore x=2.
i hope this helps :)
Answer:
1a) UCL = 14.2
LCL = 10.9
b) UCL = 15.63
LCL = 9.37
c) UCL = 16.48
LCL = 8.52
2) The difference between the limits falls close together as n increases
and the difference between the limits falls farther away from 12.5
Step-by-step explanation:
mean ( μ ) = 12.5
std ( б ) = 1.1
UCL = μ + ( n - 1 ) б / √n
LCL = μ - ( n - 1 ) б / √n
1) a) Given n = 4
UCL = 12.5 + ( 3 ) * 1.1 / 2
= 12.5 + 3.3/2 = 14.15 ≈ 14.2
LCL = 12.5 - 3.3/2 = 10.85 ≈ 10.9
b) Given n = 10
UCL = 12.5 + ( 9 ) * 1.1 /√10
= 12.5 + 3.13 = 15.63
LCL = 12.5 - 3.13 = 9.37
c) Given n = 15
UCL = 12.5 + 14 * 1.1 / √15
= 12.5 + 3.98 = 16.48
LCL = 12.5 - 3.98 = 8.52
2) As the sample size increases the difference between the limits of the control chart decreases
Hence the difference falls close together as n increases
and the difference between the limits falls farther away from 12.5
